1 - Principles of Chemist X101 Chem101ml to liter - Google Searchapp.101edu.coGmailYouTube MapsTranslateNewsQuestion 11 of 12What mass in grams of CH:OH (MM = 32.04 g/mol) would need to beadded to 240.1 g of water in order to lower the freezing point of waterby 12.0 °C? (Kf for water is 1.86 °C/m)

Answered: ss in grams of CH:OH (MM = 32.04 g/mol)…

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ss in grams of CH:OH (MM = 32.04 g/mol) would nee

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Expert Solution

Step 1

Molality (m) = moles of solute/maas of solvent(kg)

Moles = mass/MM

= w/32.04

Mass of solvent= 240.1 g = 240.1/1000 = 0.2401 kg

Molality(m) = w/32.04×0.2401

∆T_f = K_f × m

12.0 = 1.86 × w/32.04×0.2401

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