Sove for following if the 3 phase transformer configuration in Figure 6 on Workshet 3 has the pvens as listed below E) Vresistor on the load is Eline on high side 480 V Tuns ration a) 2A b) 4A c) 6.93A d) 12A - 21coil Resistance per load - 100 Efficiency F) 1-line on the low side is - 100% a) 2A b) 4A c) 6.93A d) 12A A) Elcoil on the high side is a) 480V b) 240V ) 120V d) 6928V G) l-phase on the low side is a) 2A b) 4A c) 6.93A B) Elcoil on the low side is d) 12A H) Vcoil on the low side is a) 480V b) 240V ) 120V ) 6928V a) 2A b) 4A c) 6.93A d) 12A ) Ephase on the low side is I-phase on the high side is a) 48OV b) 240V ) 120V d) 6928V a) IA b) 1.73A c) 2A d) 4A J) 1-line on the high side is D) Eresistor of the load is a) IA b) 1.73A c) 2A d) 4A a) 4OV b) 240V ) 120V 4) 6928V

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D.

E

F.

Course #1105
Transformers
Worksheet 3
Transformers
2-X
E-X
X-2
*3
PH
X4
H-4
H-2 H3
page 76
TENET
"Your Technical Education Network"
1-X
E-I
Figure 6
1-L
(H
EH
Transcribed Image Text:Course #1105 Transformers Worksheet 3 Transformers 2-X E-X X-2 *3 PH X4 H-4 H-2 H3 page 76 TENET "Your Technical Education Network" 1-X E-I Figure 6 1-L (H EH
E) Vresistor on the load is
32. Solve for following if the 3-phase transfemer configuration in Figure 6 on Worksheet 3 has the
givens as listed below:
a)
2A
b) 4A
E-line on high side
= 480 V
= 2:1/coil
c) 6.93A
d) 12A
Tums ration
Resistance per load - 100
Eficiency
F) 1-line on the low side is
= 100%
a)
2A
b) 4A
c)
A) Elcoil on the high side is
6.93A
d)
12A
a) 480V
b) 240V
G) l-phase on the low side is
c) 120V
a)
2A
d) 69.28V
b)
4A
c)
d)
6.93A
B) Elcoil on the low side is
12A
H) /coil on the low side is
a) 480V
b) 240V
c) 120V
d) 69 28V
a)
2A
Б) 4A
c)
d)
6.93A
12A
C) E-phase on the low side is
I)
I-phase on the high side is
a)
b)
c) 2A
d)
1A
a) 480V
b) 240V
c) 120V
d) 69.28V
1.73A
4A
J)
I-line on the high side is
D) Eresistor of the load is
a)
b)
IA
1.73A
c)
2A
a) 480V
b) 240V
c) 120V
d) 6928V
d) 4A
K) VA/phase of the load is
a) 120VA
b) 360VA
c) 480VA
d) 1440VA
L) 3-phase VA on the high side is
a) 120VA
b) 360VA
c) 480VA
d) 1440VA
Transcribed Image Text:E) Vresistor on the load is 32. Solve for following if the 3-phase transfemer configuration in Figure 6 on Worksheet 3 has the givens as listed below: a) 2A b) 4A E-line on high side = 480 V = 2:1/coil c) 6.93A d) 12A Tums ration Resistance per load - 100 Eficiency F) 1-line on the low side is = 100% a) 2A b) 4A c) A) Elcoil on the high side is 6.93A d) 12A a) 480V b) 240V G) l-phase on the low side is c) 120V a) 2A d) 69.28V b) 4A c) d) 6.93A B) Elcoil on the low side is 12A H) /coil on the low side is a) 480V b) 240V c) 120V d) 69 28V a) 2A Б) 4A c) d) 6.93A 12A C) E-phase on the low side is I) I-phase on the high side is a) b) c) 2A d) 1A a) 480V b) 240V c) 120V d) 69.28V 1.73A 4A J) I-line on the high side is D) Eresistor of the load is a) b) IA 1.73A c) 2A a) 480V b) 240V c) 120V d) 6928V d) 4A K) VA/phase of the load is a) 120VA b) 360VA c) 480VA d) 1440VA L) 3-phase VA on the high side is a) 120VA b) 360VA c) 480VA d) 1440VA
Expert Solution
Step 1

The line voltage on low winding is equal to the phase voltage on low voltage side which is 120 V because the windings on the low voltage side are connected in delta. The load resistors are connected in star, so the phase voltage is 1/√3 time of the line voltage on the low voltage side.

D: The phase load in the load side is equal to the voltage across each resistor because the load is connected is star. Thus, voltage per resistor is given by:

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