Sometimes you want your text to look flush. That is, to have full justification so that it is aligned along both the left and margins. To make this happen, extra spaces have to be added between words as necessary. We want to write a program to calculate the number of words on a line, the total characters in those words, and the basic gap width between those words that would produce flush text. Any leftover spaces are inserted one at a time into the gaps from left to right until there are no more leftover spaces. Assume each formatted string will be of length 80 after all those gaps are filled in with spaces. The gap width is equal to : (80 - Total Characters in all Words on Line) / (Total Words on Line - 1) Input The first line of input contains a single integer n, (1 ≤ n ≤ 1000), the number of test cases that follow. Each test case consists of one line of input containing a string of length n, (1 ≤ n ≤ 80). This string will consist of two or more words as input. A word is defined as one or more contiguous characters followed by white space (space, tab, or newline). Output For each test case, output it exactly as formatted below showing the line number, total words on the line, total characters in all words on the line, and the gap width. Use integer division for all gap width calculations, and note the denominator will never be 0 since each line will always have at least two words. Sample Input 5 When April with his sweet showers has pierced the drought of March to the root. The End Sample Output Line 1 Line 2: Line 3: words=4 chars=16 gap width=21 words=3 chars=15 gap width=32 words=5 chars=24 gap width=14 Line 4: words=3 chars=10 gap width=35 Line 5 words=2 chars-6 gap width=74
Sometimes you want your text to look flush. That is, to have full justification so that it is aligned along both the left and margins. To make this happen, extra spaces have to be added between words as necessary. We want to write a program to calculate the number of words on a line, the total characters in those words, and the basic gap width between those words that would produce flush text. Any leftover spaces are inserted one at a time into the gaps from left to right until there are no more leftover spaces. Assume each formatted string will be of length 80 after all those gaps are filled in with spaces. The gap width is equal to : (80 - Total Characters in all Words on Line) / (Total Words on Line - 1) Input The first line of input contains a single integer n, (1 ≤ n ≤ 1000), the number of test cases that follow. Each test case consists of one line of input containing a string of length n, (1 ≤ n ≤ 80). This string will consist of two or more words as input. A word is defined as one or more contiguous characters followed by white space (space, tab, or newline). Output For each test case, output it exactly as formatted below showing the line number, total words on the line, total characters in all words on the line, and the gap width. Use integer division for all gap width calculations, and note the denominator will never be 0 since each line will always have at least two words. Sample Input 5 When April with his sweet showers has pierced the drought of March to the root. The End Sample Output Line 1 Line 2: Line 3: words=4 chars=16 gap width=21 words=3 chars=15 gap width=32 words=5 chars=24 gap width=14 Line 4: words=3 chars=10 gap width=35 Line 5 words=2 chars-6 gap width=74
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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