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Some useful information's: Cv t Tv %3D d2 Po+AP Sef Cc Hlog 1+e For N.C.C. For O.C.C. Cr P. + AP if P. + AP S Pe then Sef = Hlog P. 1+e if P. + AP > Þe then use: Pe P. P. + AP. Pe Сс Cr Hlog 1 +e -Hlog 1+e Sef = %3D Pe O.C.R = P. Ty = Uav For Uav S 60% %3D T, 1.781- 0.933 log (100 - Uay) For Uay> 60%

Some useful information's: Cv t Tv %3D d2 Po+AP Sef Cc Hlog 1+e For N.C.C. For O.C.C. Cr P. + AP if P. + AP S Pe then Sef = Hlog P. 1+e if P. + AP > Þe then use: Pe P. P. + AP. Pe Сс Cr Hlog 1 +e -Hlog 1+e Sef = %3D Pe O.C.R = P. Ty = Uav For Uav S 60% %3D T, 1.781- 0.933 log (100 - Uay) For Uay> 60%

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Q2: Abuilding is 20 × 32 m in plane. The total weight of the building is 150000KN .it will be built on a 10 m deep raft foundation as shown in figure: 1. Calculate the net foundation 150000 kN pressure. 2. Calculate the final consolidation settlements of this building. 3. If the allowable settlement is 1 cm Sand y= 16 kN/m³ 5m for clay 2. Calculate the net foundation pressure that would cause 20:32 u 5 m this settlement. Clay 1 Yrat = 20 kN/m2 e, = 0.8 C, = 0.01 , C, = 0.045 P. = 230 kPa 10 m Clay 2 m, = 4. 10-$m²/kN Y sar = 18 kN/m³ 10 m mmmm. Impermeable layer Some useful information's: Cv t Tv d2 Po+AP Cc Hlog 1+e For N.C.C. Sef p. For O.C.C. P. + AP if P. + AP < P. then Ser = Cr Hlog 1+e if P. + AP > Þ. then use: Cr Hlog 1+e Pe P. P. + AP Сс Hlog Ser = Pe 1+e Pe O. C.R = P. Ty For Uav S 60% T 1.781 - 0.933 log (100 - Uay) For Uay> 60%
Transcribed Image Text:Q2: Abuilding is 20 × 32 m in plane. The total weight of the building is 150000KN .it will be built on a 10 m deep raft foundation as shown in figure: 1. Calculate the net foundation 150000 kN pressure. 2. Calculate the final consolidation settlements of this building. 3. If the allowable settlement is 1 cm Sand y= 16 kN/m³ 5m for clay 2. Calculate the net foundation pressure that would cause 20:32 u 5 m this settlement. Clay 1 Yrat = 20 kN/m2 e, = 0.8 C, = 0.01 , C, = 0.045 P. = 230 kPa 10 m Clay 2 m, = 4. 10-$m²/kN Y sar = 18 kN/m³ 10 m mmmm. Impermeable layer Some useful information's: Cv t Tv d2 Po+AP Cc Hlog 1+e For N.C.C. Sef p. For O.C.C. P. + AP if P. + AP < P. then Ser = Cr Hlog 1+e if P. + AP > Þ. then use: Cr Hlog 1+e Pe P. P. + AP Сс Hlog Ser = Pe 1+e Pe O. C.R = P. Ty For Uav S 60% T 1.781 - 0.933 log (100 - Uay) For Uay> 60%
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