Fore O, Rectangle, » Distance of Centroid fom x- axis, i-e, (7) A, = (42) (46 +19+21) = 3612 mm2 X, = 42 = 21 mm Y = A1 Y,t A2Y2 – A3Yz - A4 Y4 (AitA2- Az-Aq) & d = 46 t19+2) = 43 mm - Y = 3612)(43) + ( 1247) (5) – (26452) /23) – (10.257) (72083) 3612- +1147-2645ス - 10-25) Tore ® triangle, A2ニ (58)(85-42) = 1247 mm2 133 612.889 = 36.291 mm, 3681-6 8 8| -等 - 43 mm y = 36-2912 mm mm For ® semi- Cerele y - axis (mm) Az = T23)= 264.5) a mm 23 = 42 - 4 (23) = 32.238 mm - 23 mm. for © Quertee Clrele. Ay = A(21) = (110.25)* mm 4 X4 = 42-) = 32.238 3ス 4 Y4 = 86- 4(2.) 77.087 mm 42 x - axis (mm) Answer: V = 839, 487.1532 mm3
Fore O, Rectangle, » Distance of Centroid fom x- axis, i-e, (7) A, = (42) (46 +19+21) = 3612 mm2 X, = 42 = 21 mm Y = A1 Y,t A2Y2 – A3Yz - A4 Y4 (AitA2- Az-Aq) & d = 46 t19+2) = 43 mm - Y = 3612)(43) + ( 1247) (5) – (26452) /23) – (10.257) (72083) 3612- +1147-2645ス - 10-25) Tore ® triangle, A2ニ (58)(85-42) = 1247 mm2 133 612.889 = 36.291 mm, 3681-6 8 8| -等 - 43 mm y = 36-2912 mm mm For ® semi- Cerele y - axis (mm) Az = T23)= 264.5) a mm 23 = 42 - 4 (23) = 32.238 mm - 23 mm. for © Quertee Clrele. Ay = A(21) = (110.25)* mm 4 X4 = 42-) = 32.238 3ス 4 Y4 = 86- 4(2.) 77.087 mm 42 x - axis (mm) Answer: V = 839, 487.1532 mm3
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
Using Pappus-Guldinus Theorems
Find the volume
Transcribed Image Text:For O, Rectangle,
» Distance of Centroid from X- axis,
i-e, (y)
A, = (42) (46+19+21)
= 3612 mm
Y = A1 Yit A2Y2 - A3Yz- A4 Y4
= 21 mm -
(A,TA2- Az-A4)
& d = 46 tI9+2)
43 mm .
Tore ® triengle,
y = (3612)(43) + (1247) (E) – (26 457) /23) – (10-257) (72087)
(3612 + 1147-2645ス- 110-25)
Az =
(58)(85– 42)
= 1247 mm
2
133 612.88
3681-6 8 8|
=
36.291 mm,
- (85-42)
43
mm
y = 36.2912 mm
12 =
mm
For 3 semi- Cirele
y - axis (mm)
Az =
42 - 4 (23) =
32.238 mm
= 23 mm.
for © Quuree Arde.,
Ay = T(21 - (1l0.25)7 mm-
4
とィ= 42-4(23).
3ス
R23
32.238
4 Y4 = 86-
4(2.)
77,087 Mm
+
42
X - axis (mm)
Answer: V = 839,487.1532 mm3
R21
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