SOLVE: Use the plus four method to find P₁, P₂, and the upper and lower bound of the 90% confidence interval. Give your answers to four decimal places. PI = P₂ = lower bound: upper bound:
SOLVE: Use the plus four method to find P₁, P₂, and the upper and lower bound of the 90% confidence interval. Give your answers to four decimal places. PI = P₂ = lower bound: upper bound:
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:STATE: Lyme disease is spread in the northeastern United
States by infected ticks. The ticks are infected mainly by
feeding on mice, so more mice result in more infected ticks.
The mouse population rises and falls with the abundance of
acorns, their favored food. Experimenters studied two
similar forest areas in a year when the acorn crop failed.
They added hundreds of thousands of acorns to one area to
imitate an abundant acorn crop, while leaving the other
area untouched. The next spring, 54 of the 72 mice trapped
in the first area were in breeding condition, versus 10 of the
17 mice trapped in the second area. Estimate the difference
between the proportions of mice ready to breed in good
acorn years and bad acorn years. (Use 90% confidence. Be
sure to justify your choice of confidence interval.)
Clive G. Jones et al., "Chain reactions linking acorns to gypsy moth outbreaks
and Lyme disease risk," Science, 279 (1998), pp. 1023-1026.

Transcribed Image Text:SOLVE: Use the plus four method to find P₁, P₂, and the
upper and lower bound of the 90% confidence interval.
Give your answers to four decimal places.
PI =
P₂ =
lower bound:
upper bound:
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VIEWStep 2: Estimate the proportion of mice ready to breed in the first area
VIEWStep 3: Estimate the proportion of mice ready to breed in the second area
VIEWStep 4: Estimate the lower bound of the 90% confidence interval for the difference between the proportions
VIEWStep 5: Estimate the lower bound of the 90% confidence interval for the difference between the proportions
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