Solve this LP max z=31 +20 +2.503 8.t.. has optimal tableau So B = 1 + ₂ + 2003 2x1 + 2x3 #1, 2, 3 > 0 ča 11 02 and B-1 =3 <4 ≤6 0--1/32 and cay = and using B-¹ and B-¹cgy formulas the missing values in optimal tableau are 2.5; C = 181; 023 0 5₁15₂3 23 % 1 0 0 201 0 0 1 2 #g 81 0 1 0 rhs Z 1/2 by 1/2 ₂ 82 čs ča₁ 1/2 ā13 1 23 0 and the optimal solution for zis z = 11 Now find the maximum amount A = 2.5 that the value of c3 can be increased so that the optimal BV remains optimal.
Solve this LP max z=31 +20 +2.503 8.t.. has optimal tableau So B = 1 + ₂ + 2003 2x1 + 2x3 #1, 2, 3 > 0 ča 11 02 and B-1 =3 <4 ≤6 0--1/32 and cay = and using B-¹ and B-¹cgy formulas the missing values in optimal tableau are 2.5; C = 181; 023 0 5₁15₂3 23 % 1 0 0 201 0 0 1 2 #g 81 0 1 0 rhs Z 1/2 by 1/2 ₂ 82 čs ča₁ 1/2 ā13 1 23 0 and the optimal solution for zis z = 11 Now find the maximum amount A = 2.5 that the value of c3 can be increased so that the optimal BV remains optimal.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Solve this LP
max z = 3x1 + 2*2 + 2.5x3
8.t.
has optimal tableau.
So B =
ā13
5₁
1+ 2+ 2013
2x1 + 2x3
1, 2, 3 > 0
=
1;
1 1
0 2
and B-¹ =
15₂ 3
=
<4
<6
and using B-¹ and B-¹cgy formulas the missing values in optimal tableau are
C = 2.5; C = 3 );
131
=
28 = 0
0;
1
1
2
0 11/123
and cay = 2 3
Z 21
1
0
0
0
0
1
2 Ty
81
0 Ts Ca
1
0
ā13
ā23
rhs
Ž
$2
1/2
1 -1/2 ₁
0 1/2
5₂
and the optimal solution for zis z = 11
Now find the maximum amount A = 2.5 that the value of c can be increased so that the optimal BV remains optimal.
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