5. The height (feet) of a projectile x seconds after it is launched straight up in the air is given by f(x) =-16x? + 214x +8. Find its maximum height.

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Problem Statement

The height (feet) of a projectile \(x\) seconds after it is launched straight up in the air is given by the function \(f(x) = -16x^2 + 214x + 8\). Find its maximum height.

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### Explanation

This problem involves finding the maximum height reached by a projectile when its height as a function of time is given by a quadratic equation \(f(x) = -16x^2 + 214x + 8\).

In a quadratic equation in standard form, \(f(x) = ax^2 + bx + c\), where \(a < 0\) indicates the parabola opens downward, the maximum height can be found at the vertex of the parabola. The x-coordinate of the vertex can be found using the formula:

\[ x = \frac{-b}{2a} \]

For the given function \(f(x) = -16x^2 + 214x + 8\):

- \(a = -16\)
- \(b = 214\)

Substitute \(a\) and \(b\) into the vertex formula to find the time \(x\) at which the maximum height occurs.

\[ x = \frac{-214}{2 \cdot -16} = \frac{-214}{-32} = 6.6875 \]

Now, substitute \(x = 6.6875\) back into the original function to find the maximum height.

\[ f(6.6875) = -16(6.6875)^2 + 214(6.6875) + 8 \]

Perform the calculation to get the maximum height.

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### Detailed Calculation

1. Find the x-coordinate of the vertex:
   
   \[ x = \frac{-214}{2 \cdot -16} = \frac{-214}{-32} = 6.6875 \]

2. Substitute \( x = 6.6875 \) back into the function to get the height:

   \[ f(6.6875) = -16(6.6875)^2 + 214(6.6875) + 8 \]
   \[ f(6.6875) = -16(44.736) + 214(6.6875) + 8 \]
   \[ f(6.6875) = -715.776
Transcribed Image Text:--- ### Problem Statement The height (feet) of a projectile \(x\) seconds after it is launched straight up in the air is given by the function \(f(x) = -16x^2 + 214x + 8\). Find its maximum height. --- ### Explanation This problem involves finding the maximum height reached by a projectile when its height as a function of time is given by a quadratic equation \(f(x) = -16x^2 + 214x + 8\). In a quadratic equation in standard form, \(f(x) = ax^2 + bx + c\), where \(a < 0\) indicates the parabola opens downward, the maximum height can be found at the vertex of the parabola. The x-coordinate of the vertex can be found using the formula: \[ x = \frac{-b}{2a} \] For the given function \(f(x) = -16x^2 + 214x + 8\): - \(a = -16\) - \(b = 214\) Substitute \(a\) and \(b\) into the vertex formula to find the time \(x\) at which the maximum height occurs. \[ x = \frac{-214}{2 \cdot -16} = \frac{-214}{-32} = 6.6875 \] Now, substitute \(x = 6.6875\) back into the original function to find the maximum height. \[ f(6.6875) = -16(6.6875)^2 + 214(6.6875) + 8 \] Perform the calculation to get the maximum height. --- ### Detailed Calculation 1. Find the x-coordinate of the vertex: \[ x = \frac{-214}{2 \cdot -16} = \frac{-214}{-32} = 6.6875 \] 2. Substitute \( x = 6.6875 \) back into the function to get the height: \[ f(6.6875) = -16(6.6875)^2 + 214(6.6875) + 8 \] \[ f(6.6875) = -16(44.736) + 214(6.6875) + 8 \] \[ f(6.6875) = -715.776
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