Solve these recurrence relations together with the initial conditions given. Recall that the solu- tion to a second order recurrence relation An = C1 An-1+ C2An-2 will be of the form f(n) = a,r" + a2r". Where r1, r2 are roots to the characteristic equation of a, and ki - kor2 kor - ki a2 = with ko = ao and kį = aj. Or if the roots are repeated, it will be of the form f(n) = a\r" + a2nr". where a = ao. Find the solution for an = 8a,-1 – 16an-2 for n2 2 and ao = 1, aį = 2. Find the solution for a, = 8a,-1 – 16a„-2 for n 2 2 and ao = 5, a1 = 7. Note: This differs from the previous problem only by its initial conditions.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Solve these recurrence relations together with the initial conditions given. Recall that the solu-
tion to a second order recurrence relation
an = can-1 + C2An-2
will be of the form
f(n) = a¡r{" + a2r".
Where ri, r2 are roots to the characteristic equation of a,
and
k1 – kor2
ri- r2
kori – ki
a2 =
ri- r2
with ko = ao and k1 = a1. Or if the roots are repeated, it will be of the form
f(n) = a¡r" + a2nr".
where a1 = ao.
Find the solution for an = 8an-1 – 16an-2 for n> 2 and ao = 1, aį =2.
1.
2.
Find the solution for a, = 8an-1 - 16a,-2 for n2 2 and a = 5, a1 = 7. Note: This
differs from the previous problem only by its initial conditions.
Transcribed Image Text:Solve these recurrence relations together with the initial conditions given. Recall that the solu- tion to a second order recurrence relation an = can-1 + C2An-2 will be of the form f(n) = a¡r{" + a2r". Where ri, r2 are roots to the characteristic equation of a, and k1 – kor2 ri- r2 kori – ki a2 = ri- r2 with ko = ao and k1 = a1. Or if the roots are repeated, it will be of the form f(n) = a¡r" + a2nr". where a1 = ao. Find the solution for an = 8an-1 – 16an-2 for n> 2 and ao = 1, aį =2. 1. 2. Find the solution for a, = 8an-1 - 16a,-2 for n2 2 and a = 5, a1 = 7. Note: This differs from the previous problem only by its initial conditions.
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