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Solve the triangle ABC, if the triangle exists. B = 140.5°, c= 6.905, b= 15.715

Solve the triangle ABC, if the triangle exists. B = 140.5°, c= 6.905, b= 15.715

Trigonometry (MindTap Course List)
Trigonometry (MindTap Course List)
8th Edition
ISBN:9781305652224
Author:Charles P. McKeague, Mark D. Turner
Publisher:Charles P. McKeague, Mark D. Turner
Chapter7: Triangles
Section7.1: The Law Of Sines
Problem 52PS: Gina is standing near a building and notices that the angle of elevation to the top of the building...
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open MATH 40 PLUS - Trigonometry - 74242 Homework: Homew... Question 15, 7.2.27 Solve the triangle ABC, if the triangle exists. B = 140.5°, c= 6.905, b = 15.715 ..... Select the correct choice below and fill in the answer boxes with in the choice. O A. There is only 1 possible solution for the triangle. The measurements for the remaining angles A and C and side a are as follows. mZA = m2C = The length of side a = (Round to the nearest tenth as needed.) (Round to the nearest tenth as needed.) (Round to the nearest thousandth as needed.) O B. There are 2 possible solutions for the triangle. The measurements for the solution with the longer side a are as follows. mZA= ° m2c=° The length of side a = (Round to the nearest tenth as needed.) (Round to the nearest tenth as needed.) The measurements for the solution with the shorter side a are as follows. (Round to the nearest thousandth as needed.) mZA = m2c=° The length of side a = (Round to the nearest tenth as needed.) (Round to the nearest tenth as needed.) (Round to the nearest thousandth as needed.) O C. There are no possible solutions for the triangle. Help me solve this View an example Get more help - 16 étv MacBook Pro
Transcribed Image Text:open MATH 40 PLUS - Trigonometry - 74242 Homework: Homew... Question 15, 7.2.27 Solve the triangle ABC, if the triangle exists. B = 140.5°, c= 6.905, b = 15.715 ..... Select the correct choice below and fill in the answer boxes with in the choice. O A. There is only 1 possible solution for the triangle. The measurements for the remaining angles A and C and side a are as follows. mZA = m2C = The length of side a = (Round to the nearest tenth as needed.) (Round to the nearest tenth as needed.) (Round to the nearest thousandth as needed.) O B. There are 2 possible solutions for the triangle. The measurements for the solution with the longer side a are as follows. mZA= ° m2c=° The length of side a = (Round to the nearest tenth as needed.) (Round to the nearest tenth as needed.) The measurements for the solution with the shorter side a are as follows. (Round to the nearest thousandth as needed.) mZA = m2c=° The length of side a = (Round to the nearest tenth as needed.) (Round to the nearest tenth as needed.) (Round to the nearest thousandth as needed.) O C. There are no possible solutions for the triangle. Help me solve this View an example Get more help - 16 étv MacBook Pro
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