Solve the system by back substitution. -4x-8y-2z - 6w = -5 -5y-30z-10w = -40 - 5z-5w = - 10 - 5w= -15 ... The solution set is {0} (Type an integer or a simplified fraction.)
Solve the system by back substitution. -4x-8y-2z - 6w = -5 -5y-30z-10w = -40 - 5z-5w = - 10 - 5w= -15 ... The solution set is {0} (Type an integer or a simplified fraction.)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Solve the system by back substitution.
- 4x-8y-2z - 6w
-5
- 5y - 30z - 10w = - 40
- 5z - 5w = - 10
- 5w = -15
The solution set is {} (Type an integer or a simplified fraction.)
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