Solve the system by back substitution. -4x-8y-2z - 6w = -5 -5y-30z-10w = -40 - 5z-5w = - 10 - 5w= -15 ... The solution set is {0} (Type an integer or a simplified fraction.)
Solve the system by back substitution. -4x-8y-2z - 6w = -5 -5y-30z-10w = -40 - 5z-5w = - 10 - 5w= -15 ... The solution set is {0} (Type an integer or a simplified fraction.)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question

Transcribed Image Text:**Solving the System by Back Substitution**
Given the system of equations:
1. \(-4x - 8y - 2z - 6w = -5\)
2. \(-5y - 3z - 10w = -40\)
3. \(-5z - 5w = -10\)
4. \(-5w = -15\)
**Instructions:**
Use back substitution to solve this system.
The solution set should be entered as \(\{ \, \_\_ , \, \_\_ , \, \_\_ , \, \_\_ \, \}\) in the blanks provided. You may type an integer or a simplified fraction.
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