Solve the system by back substitution. - 4x - 8y - 2z - 6w = -1 - 4y - 24z - 8w = - 32 3z + 3w = W = 3 ... The solution set is {ODID} (Type an integer or a simplified fraction.) 263
Solve the system by back substitution. - 4x - 8y - 2z - 6w = -1 - 4y - 24z - 8w = - 32 3z + 3w = W = 3 ... The solution set is {ODID} (Type an integer or a simplified fraction.) 263
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Solve the system by back substitution.
- 4x - 8y - 2z - 6w = -1
- 4y - 24z - 8w = - 32
3z + 3w =
W =
3
..
The solution set is { O1ID}(Type an integer or a simplified fraction.)
263
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