Solve the system by back substitution. 2x+4y+z +3w= -1 y+6z+2w = 8 -2z-2w = -4 -2w=-6 *** The solution set is {0} (Type an integer or a simplified fraction.)
Solve the system by back substitution. 2x+4y+z +3w= -1 y+6z+2w = 8 -2z-2w = -4 -2w=-6 *** The solution set is {0} (Type an integer or a simplified fraction.)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Solve the system by back substitution.
2x+4y+z+3w= - 1
y+6z+2w = 8
- 2z-2w = -4
- 2w = -6
The solution set is {0}. (Type an integer or a simplified fraction.)
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