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Solve the structure of this compound by looking at the 1H, 13C NMR data provided.  You must fill all of the parts to this question in the given spaces.  Molecular formula:  C6H14N2O2

Solve the structure of this compound by looking at the 1H, 13C NMR data provided.  You must fill all of the parts to this question in the given spaces.  Molecular formula:  C6H14N2O2

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Solve the structure of this compound by looking at the 1H, 13C NMR data provided.  You must fill all of the parts to this question in the given spaces.  Molecular formula:  C6H14N2O2

5 Solvent: D₂O Field: 500 MHz (¹H): 125 MHz (13C) 1H 4.0 DEPT 135 13C 170 (1) 3.8 160 3.6 Solution of problem # 3: Degree of unsaturation: 13C NMR interpretation: DEPT interpretation: 150 Peak A (3.75 ppm) Peak D (1.72 ppm) 3.4 140 5 3.2 130 3.0 120 2.8 110 20 ¹H (ppm) 100 UC (ppm) 24 Peak B (3.01 ppm) 90 2.2 60 October 2.0 70 Peak E (1.56 ppm) Structure of unknown compound ملة (2) i 1.8 (2) 60 16 50 'H NMR interpretation (I want a picture of the fragment that you can determine from the shift and splitting): (2) 1.4 40 30 Peak C (1.90 ppm) 1.2
Transcribed Image Text:5 Solvent: D₂O Field: 500 MHz (¹H): 125 MHz (13C) 1H 4.0 DEPT 135 13C 170 (1) 3.8 160 3.6 Solution of problem # 3: Degree of unsaturation: 13C NMR interpretation: DEPT interpretation: 150 Peak A (3.75 ppm) Peak D (1.72 ppm) 3.4 140 5 3.2 130 3.0 120 2.8 110 20 ¹H (ppm) 100 UC (ppm) 24 Peak B (3.01 ppm) 90 2.2 60 October 2.0 70 Peak E (1.56 ppm) Structure of unknown compound ملة (2) i 1.8 (2) 60 16 50 'H NMR interpretation (I want a picture of the fragment that you can determine from the shift and splitting): (2) 1.4 40 30 Peak C (1.90 ppm) 1.2
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