Solve the problem using Moment -Area Method Problem IV. Determine the support reactions of the beam shown. El is constant for the entire beam. 40kN/m 20kN/m A B + 4m 4m
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Q: shear-force and bending-moment diagrams
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- 3 For the beam shown, find the reactions at the supports and plot the shear-force and bending-moment diagrams. V = 9 kN, V2 = 9 kN, V3 = 200 mm, and V4 = 1100 mm. ATAT-V3 Provide values at all key points shown in the given shear-force and bending-moment diagrams. X (mm) B A = B = C = D = E= F= P = Q = E * KN * KN * KN × KN KN x KN ✩ kN.mm *kN.mm D 0.00 Reaction force R₁ (left) = In the shear-force and bending-moment diagrams given, +V 0.00 X (mm) 6.3 kN and reaction force R2 (right) = P 11.7 kN. Q 0.00Given the simple beam as shown below. Determine the following: 100 N/m 30 N/m A 2 m B 7m mum. 2m D The External Reaction at Point B. The External Reaction at Point C.Problem 2: The beam is held in equilibrium by a roller at A and a pin at B. The beam supports a uniform distributed load (2 kip/ft) and a concentrated moment (30 kip-ft) at the locations shown. Use the equation method to solve this problem. 2 kip/ft Į 5 ft 5 ft 30 kip-ft 5 ft (a) Derive expressions for V(x) and M(x) in each section of the beam. (b) Use the results from part (a) to draw the shear force (V) and bending moment (M) diagrams for the beam. Clearly label all important values and points on the diagrams.
- Determine the ff: •Internal bending moment at point c •internal shear force at point c •internal normal force at point c Asap please.The steel box wrench (E=29,000ksi, v=0.32) is loaded with a 40-lb horizontal force and a 25-lb vertical force. Find the following for an element located at point B on Section a-a: 24 in. 1. The non-vanishing resultant internal moments on section a-a are which of the following? 4 in. a. (160 i- 600 j+960 k)in · Ib b. (-160 i+600 j+960 k ) in · lb c. (-960 i+160 j+600 k)in - lb d. (-960 i -160 ј-600 k)in-lb a e. none of the above 2. The normal and shear force components on section a-a are: a. V, = 65lb;V, = 40lb; N¸ = 25lb b. V, = 0;V, =40lb; N, = 25lb c. V, = 64;V, = 25lb; N, = 40lb d. V, =0;V, =-40lb; N¸ = -25lb e. none of the above 3. The non-vanishing stress components at point B are: 0̟ =1.60; t =-4.89ksi; а. 0, =-4.89; 7 =3.60ksi; 0, = 2.50ksi; T, d. o, = 4.91ksi; t =-4.89ksi; b. с. =-4.89ksi; е. none of the above 4. The principal stresses at point B from most tensile to most compressive are: O1,02,0; =4.16,–0.8,–5.76 b. o,,0,,0, =5.76,0,–4.16 а. O1,02,0; =1.9,-2.45,-6.8 с. d.…Determine the second moment of area (Iyy) about the centroidal y-axis for a solid homogeneous beam section where the dimensions are b = 125 mm and d = 275 mm. Give your answer in m4 to 2 significant figures.
- The beam shown in the figure is made of material with a tensile strength of 24 MPa. Accordingly, determine the maximum moment (Nm) that can be applied to the beam.Determine the internal normal force and shear force, and the bending moment in the beam at points C and D. Assume the support at B is a roller. Point C is located just to the right of the 8-kip load. For your explanation section, complete a FBD of the other side of the beam from the version you did to solve the problem. 8 kip 40 kip · ft A to to D B- 8 ft 8 ft- -8 ftModulus E of elasticity, for the ACB beam with inertia I; a- Find the elastic curve equation with the singularity equation. b- Find the reaction forces at Point A. c- Find the reaction force at Point B. (2/3) W 2W A W -L/2 L
- The simply supported beam is subjected to the force F = 700 N and the uniform distributed load with intensity w = 150 N/m. Draw the shear force and bending moment diagrams (in your homework documentation) and determine the equations for V(r) and M(x). Take a = 0 at point A. 19 F a Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 5.2 m 2.6 m 3.12 m Support Reactions The reaction at A is N. The reaction at D is N. Shear Force and Bending Moment Equations In section AB: V(x)= N and M(x)= N-m. In section BC: v(x)- N and M(x)= N-m. In section CD: V(x)- N and M(x)= N-m. A4. For the beam shown, find the reactions at the supports and plot the shear-force and bending moment diagrams. Label the diagrams properly and provide values at all key points. y 400 lbf Hinge A B AC R₁ 4 in 4 in 2 in 40 lbf/in R2 10 in D R3 -XMo = M-400×0.15cos30-320x 0.3 = 0 160 mm 400 N M = 148 Nm CCW Example : Replace the three forces acting on the bent beam by a single equivalent force R. Specify the distance x from the point O in which the line of action of R passes. 200 N 160 N 250 mm 250 mm 250 mm 125 mm 240 N