Solve the initial value problem. y" – 2y' + 2y = e; y(0) = 0, y'(0) = 7 Chapter 6, Section 6.2, Go Tutorial Problem 16 Good. Find Y(s). 1 7 Y(s) = (s + 1) (s² – 2s + 2) s2 2s + 2 - 1 Y(s) = s + 1 7 - 2s + 2 7 1 Y(s) = s + 1 s2 – 2s + 2 7 Y(s) = (s + 1) (s² – 2s + 2) - 2.s + 2) 1 7 Y(s) = (s + 1) (s² 2s + 2) s2 2s + 2 +

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
Find y(t).
y(t) =
37
y(t) =
se'sint
37
-e'sint + ÷e'cost +
5
1
1
y(1) =
5
37
'sint –
1
cost +
1
y(t) =
37
y(t) =
1
1
sint
je'cost +e
Transcribed Image Text:Find y(t). y(t) = 37 y(t) = se'sint 37 -e'sint + ÷e'cost + 5 1 1 y(1) = 5 37 'sint – 1 cost + 1 y(t) = 37 y(t) = 1 1 sint je'cost +e
Solve the initial value problem.
y" – 2y' + 2y = e: y(0) = 0, y'(0) = 7
Chapter 6, Section 6.2, Go Tutorial Problem 16
Good.
Find Y(s).
1
7
Y(s) =
(s + 1) (s² – 2s + 2)
s2 – 2s + 2
1
Y(s) =
7
s + 1
s2 – 2s + 2
1
Y(s) =
s + 1
7
s2 – 2s + 2
7
Y(s) =
(s + 1)(s²
- 2s + 2)
1
7
Y(s) =
(s + 1) (s² – 2s + 2)
s2 – 2s + 2
Attempts: 1 of 1 used
Transcribed Image Text:Solve the initial value problem. y" – 2y' + 2y = e: y(0) = 0, y'(0) = 7 Chapter 6, Section 6.2, Go Tutorial Problem 16 Good. Find Y(s). 1 7 Y(s) = (s + 1) (s² – 2s + 2) s2 – 2s + 2 1 Y(s) = 7 s + 1 s2 – 2s + 2 1 Y(s) = s + 1 7 s2 – 2s + 2 7 Y(s) = (s + 1)(s² - 2s + 2) 1 7 Y(s) = (s + 1) (s² – 2s + 2) s2 – 2s + 2 Attempts: 1 of 1 used
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