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Solve the initial value problem. Chapter 6, Section 6.2, Go Tutorial Problem 12 Good. Find Y (s). Y (s) = Y (s) = Y (s) = Y (s) = 4s + 13 s² +65 +25 s² +65 +25 Find y(t). 4s + 13 4s + 13 s² +65 +25 4s - 13 s² +65 +25 Chapter 6, Section 6.2, Go Tutorial Problem 12 ○ y(t) = e ³ (cost + sint) Oy(t) = ○ y(t) = y(t) = y(t) = y" + 6y + 25y = 0; y(0) = 4 y (0) = -11 ¹ (4 cos3r + sin3r) e³ (16 sint + sin4r) (16 cos4r + sin4r) e³ (16 cos4r + sin4t)

Solve the initial value problem. Chapter 6, Section 6.2, Go Tutorial Problem 12 Good. Find Y (s). Y (s) = Y (s) = Y (s) = Y (s) = 4s + 13 s² +65 +25 s² +65 +25 Find y(t). 4s + 13 4s + 13 s² +65 +25 4s - 13 s² +65 +25 Chapter 6, Section 6.2, Go Tutorial Problem 12 ○ y(t) = e ³ (cost + sint) Oy(t) = ○ y(t) = y(t) = y(t) = y" + 6y + 25y = 0; y(0) = 4 y (0) = -11 ¹ (4 cos3r + sin3r) e³ (16 sint + sin4r) (16 cos4r + sin4r) e³ (16 cos4r + sin4t)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Solve the initial value problem. Chapter 6, Section 6.2, Go Tutorial Problem 12 Good. Find Y (s). Y(s) = Y (s) = Y(s) = Y(s) = Find y (1). 4s + 13 s² + 6s + 25 s² + 6s+25 4s +13 Chapter 6, Section 6.2, Go Tutorial Problem 12 y(t) = $² + 6s + 25 4s - 13 s² + 6s + 25 y(t) = e y(t) = 4s + 13 ₂-31 (cost + sint) y(t) = e(4 cos3r + sin3r) y(t) = e(16 sint + sin4t) 1 e³¹ (16 cos4r + sin41) 1 -31 y" + 6y + 25y = 0; y(0) = 4y (0) = - 11 (16 cos4t + sin4t)
Transcribed Image Text:Solve the initial value problem. Chapter 6, Section 6.2, Go Tutorial Problem 12 Good. Find Y (s). Y(s) = Y (s) = Y(s) = Y(s) = Find y (1). 4s + 13 s² + 6s + 25 s² + 6s+25 4s +13 Chapter 6, Section 6.2, Go Tutorial Problem 12 y(t) = $² + 6s + 25 4s - 13 s² + 6s + 25 y(t) = e y(t) = 4s + 13 ₂-31 (cost + sint) y(t) = e(4 cos3r + sin3r) y(t) = e(16 sint + sin4t) 1 e³¹ (16 cos4r + sin41) 1 -31 y" + 6y + 25y = 0; y(0) = 4y (0) = - 11 (16 cos4t + sin4t)
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