Solve the initial value problem: Y(r) = xy + y² y' = 2 , y(−1) = −1 Note that we've been given an intial value of the form y(a) = b where a < 0. This only determines a solution corresponding to the left half of the graph of ln(|x|), i.e., the part of the graph corresponding to negative values of x. Therefore, it's best to write In(-x) instead of ln(|x|), since the right half of the graph is not determined by the initial condition given.

Solve the initial value problem: Y(r) = xy + y² y' = 2 , y(−1) = −1 Note that we've been given an intial value of the form y(a) = b where a < 0. This only determines a solution corresponding to the left half of the graph of ln(|x|), i.e., the part of the graph corresponding to negative values of x. Therefore, it's best to write In(-x) instead of ln(|x|), since the right half of the graph is not determined by the initial condition given.

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)

6th Edition

ISBN:9781337111348

Author:Bruce Crauder, Benny Evans, Alan Noell

Publisher:Bruce Crauder, Benny Evans, Alan Noell

Chapter2: Graphical And Tabular Analysis

Section2.1: Tables And Trends

Problem 1TU: If a coffee filter is dropped, its velocity after t seconds is given by v(t)=4(10.0003t) feet per...

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