Solve the initial value problem y'' + 2y' + 26y = y(t) √ 2 2 ≤ t < 3 [0 t≥ 3 or t< 2 ' Give the solution for 2 < t < 3. y(0) = y'(0) = 0

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A: NOTE: Refresh your page if you can't see any equations. . here we have x=1 and y=4

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