Find y' in y=sin¹ (5x5+2x) + Tan-¹ (x²) 1 1 1+x² -(5x5+2x)² A. y' B. y' C. y' D. y' = = 25x¹+2 1-(5x5+2x)² 25x¹+2 √1-(5x5+2x)² 25x²+2 /1+(5x5+2x)² E. NO correct choices + + + 2x 1+x² 2x 1+x4 2x 1+x4

Q: Find y' if y=sin-¹4x³. Oy'= 1 √1-16x6 Oy'=-- Oy': 1 √1-16x6 Oy'=- 12x² √1-16x6 12x² √1-16x6

A: Given thaty = We find y'.

Q: how does dy/dx(tanx) become sec^2x

A: It is a standard derivative formula, whose derivation can be found mentioned below.

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A:

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A:

Q: verify cos(3x) = 4cos^3 (x) - 3cos(x)

A: We know that  cos(A+B)=cosAcosB-sinAsinB Therefore cos(3x)=cos(2x+x)=cos(2x)cos(x)-sin(2x)sin(x)

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A:

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A: We have to find the derivative.

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A: We have to find the function value

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A:

Q: if S 3 then S f(x) dx = 43 and I f(x) f(x) dx = -2 -1 √ (3 Sin (x) - 4 fcx)) dx = ? -1

A:

Q: 19) Find f' if f(x)= sec² x 83√x

A: