Solve the given linear programming problem using the table method. A table of basic solutions is provided to the right. x₁ 0 Maximize P=22x₁ + 10x₂ 3x₁ + 7x₂ < 42 x₁ + 2x₂ s13 x₁, x₂ > 0 The maximum value of P is P=, occuring at x₁ = ₁x₂ = (Type integers or fractions.) 0 0 14 13 7 x2 0 6 6.5 0 0 3 5₁ 42 0 -3.5 0 3 0 WEEB 5₂ 13 1 0 -1 0 0 Feasible Feasible Not feasible Not feasible Feasible Feasible

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Solve the given linear programming problem using the table method. A table of basic solutions is provided to the right. x₁
0
0
Maximize P=22x₁ + 10x₂
3x₁ + 7x₂ ≤ 42
X₁ + 2x₂ ≤ 13
Χρ. Χ., ΣΟ
The maximum value of P is P=
(Type integers or fractions.)
-, occuring at x₁ =₁₂2-0
0
14
13
7
x₂
0
6
6.5
0
0
3
S₁
42
0
-3.5
0
3
0
...
5₂
13 Feasible
1
Feasible
0
0
0
1
Not feasible
Not feasible
Feasible
Feasible
Transcribed Image Text:← Solve the given linear programming problem using the table method. A table of basic solutions is provided to the right. x₁ 0 0 Maximize P=22x₁ + 10x₂ 3x₁ + 7x₂ ≤ 42 X₁ + 2x₂ ≤ 13 Χρ. Χ., ΣΟ The maximum value of P is P= (Type integers or fractions.) -, occuring at x₁ =₁₂2-0 0 14 13 7 x₂ 0 6 6.5 0 0 3 S₁ 42 0 -3.5 0 3 0 ... 5₂ 13 Feasible 1 Feasible 0 0 0 1 Not feasible Not feasible Feasible Feasible
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