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Solve the linear programming problem using the simplex method. P = 4x₂ + 2x₂-x₂ X₁ + X₂-X3 55 2x, +4x₂+3x3 $15 X₁, X₂, X3 20 Maximize subject to Use the simplex method to solve the problem. Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. ⒸA. The maximum value of P is when x₁-x₂- and X- (Simplify your answers. Type integers or decimals rounded to the nearest tenth as needed.). OR There is no optimal solution.

Solve the linear programming problem using the simplex method. P = 4x₂ + 2x₂-x₂ X₁ + X₂-X3 55 2x, +4x₂+3x3 $15 X₁, X₂, X3 20 Maximize subject to Use the simplex method to solve the problem. Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. ⒸA. The maximum value of P is when x₁-x₂- and X- (Simplify your answers. Type integers or decimals rounded to the nearest tenth as needed.). OR There is no optimal solution.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Solve the linear programming problem using the simplex method. P=4x₁ + 2x₂-x3 Maximize subject to X₁ + X₂ X3 55. 2x₁ +4x₂ + 3x3 5 15 X₁ X2 X3 20 Use the simplex method to solve the problem. Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. ⒸA. The maximum value of P is when x₁=x₂- and x3 =1 (Simplify your answers. Type integers or decimals rounded to the nearest tenth as needed.) OB There is no optimal solution.
Transcribed Image Text:Solve the linear programming problem using the simplex method. P=4x₁ + 2x₂-x3 Maximize subject to X₁ + X₂ X3 55. 2x₁ +4x₂ + 3x3 5 15 X₁ X2 X3 20 Use the simplex method to solve the problem. Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. ⒸA. The maximum value of P is when x₁=x₂- and x3 =1 (Simplify your answers. Type integers or decimals rounded to the nearest tenth as needed.) OB There is no optimal solution.
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