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Solve the following problems completely. 1. Let [02 4 5 A = 6 5 U= 1 0 -31 1 D= 5 0 2 1.5 0 -3.0. V= 052 B = 5 34 1-2 4 -21 2 -63 E = 3 4 033 -5 w=-30 10 C = Find the following expressions. State reasons when they are not defined. a. 3A, 0.5B, 3A +0.5B, 3A +0.5B + C b. (4 x 3)A, 4(3A), 14B-3B, 11B c. (C+D) + E, (D+E) + C, 0(C-E) + 4D, A - OC d. (2 x 7)C, 2(7C), -D +0E, E-D+C+u e. (u + v)-w, u +(v-w), C+0w, OE+u-v 240 5 21 -2 4

Solve the following problems completely. 1. Let [02 4 5 A = 6 5 U= 1 0 -31 1 D= 5 0 2 1.5 0 -3.0. V= 052 B = 5 34 1-2 4 -21 2 -63 E = 3 4 033 -5 w=-30 10 C = Find the following expressions. State reasons when they are not defined. a. 3A, 0.5B, 3A +0.5B, 3A +0.5B + C b. (4 x 3)A, 4(3A), 14B-3B, 11B c. (C+D) + E, (D+E) + C, 0(C-E) + 4D, A - OC d. (2 x 7)C, 2(7C), -D +0E, E-D+C+u e. (u + v)-w, u +(v-w), C+0w, OE+u-v 240 5 21 -2 4

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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the following problems completely. 1. Let Solve [02 4 A=6 5 5 1 0 -3 D = U= -4 1 0 5 2 1.5 0 -3.0] V = 0 B = 5 3 -2 4 E= 5 2 4 -2 033 247 W = -5 -30 10 C= Find the following expressions. State reasons when they are not defined. a. 3A, 0.5B, 3A +0.5B, 3A +0.5B + C b. (4 x 3)A, 4(3A), 14B-3B, 11B c. (C+D) + E, (D+E) + C, 0(C-E) + 4D, A - OC d. (2 x 7)C, 2(7C), -D+0E, E-D+C+u e. (u + v)-w, u+(v-w), C+0w, OE+u-v 5 21
Transcribed Image Text:the following problems completely. 1. Let Solve [02 4 A=6 5 5 1 0 -3 D = U= -4 1 0 5 2 1.5 0 -3.0] V = 0 B = 5 3 -2 4 E= 5 2 4 -2 033 247 W = -5 -30 10 C= Find the following expressions. State reasons when they are not defined. a. 3A, 0.5B, 3A +0.5B, 3A +0.5B + C b. (4 x 3)A, 4(3A), 14B-3B, 11B c. (C+D) + E, (D+E) + C, 0(C-E) + 4D, A - OC d. (2 x 7)C, 2(7C), -D+0E, E-D+C+u e. (u + v)-w, u+(v-w), C+0w, OE+u-v 5 21
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