Solve the following differential equation. 6ty 1+ t² (1+1²)+C (1+1²) (1+²)² +C y= (1+1²) ²+3+0 y= =f0 __(+1) = f( y= 3(1+²) ³+C (1+12) (1+²) ³+C (+1) = fi fip dt + = 9t
Solve the following differential equation. 6ty 1+ t² (1+1²)+C (1+1²) (1+²)² +C y= (1+1²) ²+3+0 y= =f0 __(+1) = f( y= 3(1+²) ³+C (1+12) (1+²) ³+C (+1) = fi fip dt + = 9t
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![Solve the following differential equation.
6ty
1+1²
y =
y =
y=
(1+1²)+C
(1+1²)
<=fi
(1+1²)² +0
(1+2)
(2+1) = f(
+31 +0
3(1+2) ³+C
(1+72)6
(1+²) ³+C
(141²)
fip
dt
+
= 9t](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F55ae2c3d-db8a-4868-8838-b7d4cd87465a%2Fe4b0155a-c750-4632-95dc-7fc940701342%2F1pu3qza_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Solve the following differential equation.
6ty
1+1²
y =
y =
y=
(1+1²)+C
(1+1²)
<=fi
(1+1²)² +0
(1+2)
(2+1) = f(
+31 +0
3(1+2) ³+C
(1+72)6
(1+²) ³+C
(141²)
fip
dt
+
= 9t
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