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Solve the equation and inequalities. Write the solution sets in interval notation if possible. (a) (2x-7)(x-8)=0 (b) (2x-7)(x-8) <0 (c) (2x-7)(x-8) ≤0 (d) (2x-7)(x-8)>0 (e) (2x-7)(x-8) 20

Solve the equation and inequalities. Write the solution sets in interval notation if possible. (a) (2x-7)(x-8)=0 (b) (2x-7)(x-8) <0 (c) (2x-7)(x-8) ≤0 (d) (2x-7)(x-8)>0 (e) (2x-7)(x-8) 20

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Solving Equations and Inequalities **Instructions:** Solve the equations and inequalities given below. Write the solution sets in interval notation if possible. #### Problems: (a) \((2x - 7)(x - 8) = 0\) (b) \((2x - 7)(x - 8) < 0\) (c) \((2x - 7)(x - 8) \leq 0\) (d) \((2x - 7)(x - 8) > 0\) (e) \((2x - 7)(x - 8) \geq 0\) --- **Part 1 of 5** **(a) \((2x - 7)(x - 8) = 0\)** The solution set is: - There is a graphical user interface in the image with various symbols. Users need to select the correct symbols to represent the solution set correctly. In this case, the solutions to the equation \((2x - 7)(x - 8) = 0\) would be: - \(2x - 7 = 0\) implies \(x = \frac{7}{2} = 3.5\) - \(x - 8 = 0\) implies \(x = 8\) Therefore, the solution set is: \(\left\{ 3.5, 8 \right\}\) **To Input the Solution Set:** - Open the solution input area. - Select the bracketing symbols (curly braces) representing a set. - Input the values \(3.5\) and \(8\) within these brackets. For visual understanding: - The interface displays clickable options for various interval notations and their combinations. Ensure to choose correctly to match the solution format expected.
Transcribed Image Text:### Solving Equations and Inequalities **Instructions:** Solve the equations and inequalities given below. Write the solution sets in interval notation if possible. #### Problems: (a) \((2x - 7)(x - 8) = 0\) (b) \((2x - 7)(x - 8) < 0\) (c) \((2x - 7)(x - 8) \leq 0\) (d) \((2x - 7)(x - 8) > 0\) (e) \((2x - 7)(x - 8) \geq 0\) --- **Part 1 of 5** **(a) \((2x - 7)(x - 8) = 0\)** The solution set is: - There is a graphical user interface in the image with various symbols. Users need to select the correct symbols to represent the solution set correctly. In this case, the solutions to the equation \((2x - 7)(x - 8) = 0\) would be: - \(2x - 7 = 0\) implies \(x = \frac{7}{2} = 3.5\) - \(x - 8 = 0\) implies \(x = 8\) Therefore, the solution set is: \(\left\{ 3.5, 8 \right\}\) **To Input the Solution Set:** - Open the solution input area. - Select the bracketing symbols (curly braces) representing a set. - Input the values \(3.5\) and \(8\) within these brackets. For visual understanding: - The interface displays clickable options for various interval notations and their combinations. Ensure to choose correctly to match the solution format expected.
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