Solve the equation (4ху + Зу? — х)ӑx + x(х + 2у)dy — 0. а. 4ху+ 4y? — х — с с. х?(4ху — 4y? — х)— с e. none of the choices b. x(4ху + 4y? — х)%— с d. x3(4x? у + 4y? + x?)— с

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Solve the equation (4xy+ 3y² – x)dx+ x(x + 2y)dy= 0.
а. 4ху+ 4y? — х %3D с
с. х?(4ху—4у2 — х)— с
e. none of the choices
b. x³(4xy + 4y² – x) = c
d. x³(4xy+ 4y? + x²) = c
Transcribed Image Text:Solve the equation (4xy+ 3y² – x)dx+ x(x + 2y)dy= 0. а. 4ху+ 4y? — х %3D с с. х?(4ху—4у2 — х)— с e. none of the choices b. x³(4xy + 4y² – x) = c d. x³(4xy+ 4y? + x²) = c
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