SOLVE STEP BY STEP IN DIGITAL FORMAT ***** Find the equation of the circumference of radius {√2 2 and that passes through the intersections of the circumferences x² + y² + 2x - 6y - 16 = 0 x² + y² - 6x + 2y = 0

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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SOLVE STEP BY STEP IN DIGITAL FORMAT
******
Find the equation of the circumference of radius {√2 2 and that
passes through the intersections of the circumferences x² + y² + 2x - 6y - 16 = 0
x² + y² - 6x + 2y = 0
Transcribed Image Text:SOLVE STEP BY STEP IN DIGITAL FORMAT ****** Find the equation of the circumference of radius {√2 2 and that passes through the intersections of the circumferences x² + y² + 2x - 6y - 16 = 0 x² + y² - 6x + 2y = 0
Expert Solution
Step 1

Let the equation of the circumference be 

    (x - a)+ (y - b)= r2 [general equation of a circle with center (a, b) ans radius r]

Here, r = 5√2/2 => r= (5√2/2)2 = 50/4 = 25/2

So, the equation becomes

       (x - a)+ (y - b)= 25/2 . . . . . (1) 

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