SOLVE STEP BY STEP IN DIGITAL FORMAT ***** Find the equation of the circumference of radius {√2 2 and that passes through the intersections of the circumferences x² + y² + 2x - 6y - 16 = 0 x² + y² - 6x + 2y = 0
SOLVE STEP BY STEP IN DIGITAL FORMAT ***** Find the equation of the circumference of radius {√2 2 and that passes through the intersections of the circumferences x² + y² + 2x - 6y - 16 = 0 x² + y² - 6x + 2y = 0
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Expert Solution
Step 1
Let the equation of the circumference be
(x - a)2 + (y - b)2 = r2 [general equation of a circle with center (a, b) ans radius r]
Here, r = 5√2/2 => r2 = (5√2/2)2 = 50/4 = 25/2
So, the equation becomes
(x - a)2 + (y - b)2 = 25/2 . . . . . (1)
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