Solve K = 2MN + 2ML for M. M=

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Problem:**

Solve \( W = 2ZX + 2ZY \) for \( Z \).

**Solution:**

\[ Z = \frac{W}{2X + 2Y} \]

This solution involves isolating \( Z \) on one side of the equation by dividing both sides by the expression \( 2X + 2Y \). This results in the formula shown, which expresses \( Z \) in terms of \( W \), \( X \), and \( Y \).
Transcribed Image Text:**Problem:** Solve \( W = 2ZX + 2ZY \) for \( Z \). **Solution:** \[ Z = \frac{W}{2X + 2Y} \] This solution involves isolating \( Z \) on one side of the equation by dividing both sides by the expression \( 2X + 2Y \). This results in the formula shown, which expresses \( Z \) in terms of \( W \), \( X \), and \( Y \).
**Problem Statement:**

Solve for \( M \) in the equation \( K = 2MN + 2ML \).

**Solution:**

To isolate \( M \), follow these steps:

1. Factor out \( M \) from the right side of the equation:

   \[
   K = M(2N + 2L)
   \]

2. Divide both sides by \( (2N + 2L) \) to solve for \( M \):

   \[
   M = \frac{K}{2N + 2L}
   \]

**Final Answer:**

\[ M = \frac{K}{2N + 2L} \]
Transcribed Image Text:**Problem Statement:** Solve for \( M \) in the equation \( K = 2MN + 2ML \). **Solution:** To isolate \( M \), follow these steps: 1. Factor out \( M \) from the right side of the equation: \[ K = M(2N + 2L) \] 2. Divide both sides by \( (2N + 2L) \) to solve for \( M \): \[ M = \frac{K}{2N + 2L} \] **Final Answer:** \[ M = \frac{K}{2N + 2L} \]
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