solve for x. √2x = 8 x= 64 x= 4 x= 32 X= 16

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter11: Rational And Irrational Numbers
Section: Chapter Questions
Problem 20CT
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**Problem: Solve for \( x \)**

Given:

\[ \sqrt{2x} = 8 \]

Possible solutions:
- \( x = 64 \)
- \( x = 4 \)
- \( x = 32 \)
- \( x = 16 \)

To solve for \( x \), start by squaring both sides of the equation to eliminate the square root.

\[ (\sqrt{2x})^2 = 8^2 \]

\[ 2x = 64 \]

Next, divide both sides by 2 to isolate \( x \).

\[ x = \frac{64}{2} \]

\[ x = 32 \]

Therefore, the solution to the equation is \( x = 32 \).
Transcribed Image Text:**Problem: Solve for \( x \)** Given: \[ \sqrt{2x} = 8 \] Possible solutions: - \( x = 64 \) - \( x = 4 \) - \( x = 32 \) - \( x = 16 \) To solve for \( x \), start by squaring both sides of the equation to eliminate the square root. \[ (\sqrt{2x})^2 = 8^2 \] \[ 2x = 64 \] Next, divide both sides by 2 to isolate \( x \). \[ x = \frac{64}{2} \] \[ x = 32 \] Therefore, the solution to the equation is \( x = 32 \).
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