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Solve for the velocity (v) and position (x) of the free-falling bungee jumper using the fourth-order Runge-Kutta Method. Assuming that at t = 0 sec, x = v = 0, and calculate x and v when t = 2 sec with a step size of 2 sec (one step required). The gravitational acceleration, g is 9.81 m/s², and the jumper has a mass (m) of 70 kg with a drag coefficient ca of 0.25 kg/m. The governing equations are following. dv dt dx dt = g V Cd | E m 2 v²

Solve for the velocity (v) and position (x) of the free-falling bungee jumper using the fourth-order Runge-Kutta Method. Assuming that at t = 0 sec, x = v = 0, and calculate x and v when t = 2 sec with a step size of 2 sec (one step required). The gravitational acceleration, g is 9.81 m/s², and the jumper has a mass (m) of 70 kg with a drag coefficient ca of 0.25 kg/m. The governing equations are following. dv dt dx dt = g V Cd | E m 2 v²

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Solve for the velocity (v) and position (x) of the free-falling bungee jumper using the fourth-order Runge-Kutta Method. Assuming that at t = 0 sec, x = v= 0, and calculate x and v when t = 2 sec with a step size of 2 sec (one step required). The gravitational acceleration, g is 9.81 m/s², and the jumper has a mass (m) of 70 kg with a drag coefficient ca of 0.25 kg/m. The governing equations are following. dv dt dx dt g || m
Transcribed Image Text:Solve for the velocity (v) and position (x) of the free-falling bungee jumper using the fourth-order Runge-Kutta Method. Assuming that at t = 0 sec, x = v= 0, and calculate x and v when t = 2 sec with a step size of 2 sec (one step required). The gravitational acceleration, g is 9.81 m/s², and the jumper has a mass (m) of 70 kg with a drag coefficient ca of 0.25 kg/m. The governing equations are following. dv dt dx dt g || m
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