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Solve for the value of C in the equation: (2xy4e³ + 2xy³ + y)dx + (x²yªe¥ − x²y² – 3x)dy = 0 when y(1) = 1 - OA1 O B.2 Ос. 3 O D.-1 O E. None of the Choices

Solve for the value of C in the equation: (2xy4e³ + 2xy³ + y)dx + (x²yªe¥ − x²y² – 3x)dy = 0 when y(1) = 1 - OA1 O B.2 Ос. 3 O D.-1 O E. None of the Choices

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Solve for the value of C in the equation: (2xy4e³ + 2xy³ + y)dx + (x²yªe¥ − x²y² – 3x)dy = 0 when y(1) = 1 - - O A. 1 OB. 2 O c. 3 O D.-1 O E. None of the Choices
Transcribed Image Text:Solve for the value of C in the equation: (2xy4e³ + 2xy³ + y)dx + (x²yªe¥ − x²y² – 3x)dy = 0 when y(1) = 1 - - O A. 1 OB. 2 O c. 3 O D.-1 O E. None of the Choices
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