Solve the given equation.. (3x?у +2ху + у?)аdx + (x2 + у?)dy %3D0 (3x?y+y)e3x = C (3x?y + y³)e3x = C (3xy + y³)e3x = C d. (3x?y+y?)eX = C e. (3x?y3 + y?)e3x = C а. b. с.
Solve the given equation.. (3x?у +2ху + у?)аdx + (x2 + у?)dy %3D0 (3x?y+y)e3x = C (3x?y + y³)e3x = C (3xy + y³)e3x = C d. (3x?y+y?)eX = C e. (3x?y3 + y?)e3x = C а. b. с.
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Solve the given equation..
(3x?y+2xy+ y³)dx + (x² + y?)dy = 0
a. (3x?y + y)e3x = C
(3x?y + y³)e3* = C
(3xy + y³)e3x = C
d. (3x?y+ y?)e* = C
e. (3x?y3 + y?)e3x = C
b.
с.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd4547047-60f8-4c2e-a99a-fdfbb854bef3%2F943d7314-f3d9-4c0b-858f-386ff8ecad9f%2F8m7asmd_processed.png&w=3840&q=75)
Transcribed Image Text:Solve the given equation..
(3x?y+2xy+ y³)dx + (x² + y?)dy = 0
a. (3x?y + y)e3x = C
(3x?y + y³)e3* = C
(3xy + y³)e3x = C
d. (3x?y+ y?)e* = C
e. (3x?y3 + y?)e3x = C
b.
с.
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