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Solve for the moment of inertia, about the x-axis at the centroid. Using the parallel axis theorem, solve for the moment of inertia, about the x-axis at the top of the shape.

Solve for the moment of inertia, about the x-axis at the centroid. Using the parallel axis theorem, solve for the moment of inertia, about the x-axis at the top of the shape.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Textbook: Strength of Materials

 

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The cross section of a beam is shown below. The formula for the Moment of Inertia about the x-axis at the centroid of the section is shown below. Outer Diameter = 50 mm Inner Diameter = 40 mm Ixc = (douter - dinner) dinmer) 64 a) Solve for the moment of inertia, about the x-axis at the centroid. b) Using the parallel axis theorem, solve for the moment of inertia, about the x-axis at the top of the shape.
Transcribed Image Text:The cross section of a beam is shown below. The formula for the Moment of Inertia about the x-axis at the centroid of the section is shown below. Outer Diameter = 50 mm Inner Diameter = 40 mm Ixc = (douter - dinner) dinmer) 64 a) Solve for the moment of inertia, about the x-axis at the centroid. b) Using the parallel axis theorem, solve for the moment of inertia, about the x-axis at the top of the shape.
Formula Sheet Centre of Gravity and Moment of Inertia ΣΑ ΣΑ EA, ΣΑ I, = I, + Ad² I¸ =E(!.)+ E(Ad²) 1, = E(!.)+ y Axial Stress and Internal Forces ΣΕ, -0 Σ , =0 ΣΜ=0 o = P/ A T =V | A S.F. = o alow /o. allow actual Strain PL 8 = AE · E \ateral V = E = E = L E axial
Transcribed Image Text:Formula Sheet Centre of Gravity and Moment of Inertia ΣΑ ΣΑ EA, ΣΑ I, = I, + Ad² I¸ =E(!.)+ E(Ad²) 1, = E(!.)+ y Axial Stress and Internal Forces ΣΕ, -0 Σ , =0 ΣΜ=0 o = P/ A T =V | A S.F. = o alow /o. allow actual Strain PL 8 = AE · E \ateral V = E = E = L E axial
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