In the circuit is acircuit that is only a little different to the one in the course notes, ithas an extra resistor across the input V*.a non-invertingan inverting OpAmp-1.829VVoutR156k2R3180KOR2150kOIf we want to analyse this circuit, we need to know what effectthat resistor has on the circuit.Let's begin with what you have been taught about circuit theory.The Vin and V+ are on the same nodethere is no resistancebetween them, and therefore the voltage on V* is -1.829 V. So, theresistor has no effect on our analysis.You see that R3 and R2 form a voltage divider - but how can weknow this? What about the input V' of the OpAmp, wont it havean effect?The key is that there is no current into V- as the input resistance ofan OpAmp inputs is on. This means all the current through R3will go through R2, so it will have no effect on the voltage dividerand can be excluded from our model.This means we can redraw the circuit like this.R2V-R3Vout(=Vin)OVSolve for:1. Current A1:uA2. Voltage Vout:3. Gain =|

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Answered: Solve for: 1. Current Al: uA 2. Voltage…

Engineering

Electrical Engineering

Solve for: 1. Current Al: uA 2. Voltage Vout: V 3. Gain =

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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e 9:27 E118% ", OON 36 For the following circuit in the figure below. Determine Vp-Va ( in units of V) for ɛ = 47.9 V. a 20 50 Select one: A. 9.58 B. -7.98 C. -39.92 D. -9.58 E. 7.98 Previous page Next page O