Solve both image questions please. Thank you.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Solve both image questions please. Thank you.

**Problem Statement:**

A 75 kg block is sliding down a 20-degree incline. The coefficient of friction between the block and the incline is 0.21. Find the **ACCELERATION** down the ramp.

**Diagram Explanation:**

The diagram illustrates a block on an inclined plane:

- The block is represented as a rectangle on the incline.
- The incline is at a 20-degree angle to the horizontal.
- The mass of the block is given as \( M = 75 \, \text{kg} \).
- The coefficient of friction is \(\mu = 0.21\).
- The angle of the incline is specified as \( 20^\circ \).

A box is provided for entering the calculated acceleration value.
Transcribed Image Text:**Problem Statement:** A 75 kg block is sliding down a 20-degree incline. The coefficient of friction between the block and the incline is 0.21. Find the **ACCELERATION** down the ramp. **Diagram Explanation:** The diagram illustrates a block on an inclined plane: - The block is represented as a rectangle on the incline. - The incline is at a 20-degree angle to the horizontal. - The mass of the block is given as \( M = 75 \, \text{kg} \). - The coefficient of friction is \(\mu = 0.21\). - The angle of the incline is specified as \( 20^\circ \). A box is provided for entering the calculated acceleration value.
**Problem 4:** Rachel pushes down on a stationary 33 kg block with a force of 330 N at an angle of 28° below the horizontal. If the coefficient of friction between the block and the ground is 0.17, find the acceleration of the block.

**Diagram Explanation:**

There is a diagram illustrating the scenario:
- A block on the ground.
- An arrow indicating a force being applied at an angle of 28° below the horizontal line representing the ground level.
- The angle of 28° is marked between the arrow (force vector) and the horizontal.

To solve this problem, begin by resolving the applied force into horizontal and vertical components. Then calculate the net force considering friction, and finally use Newton's second law to find the acceleration.
Transcribed Image Text:**Problem 4:** Rachel pushes down on a stationary 33 kg block with a force of 330 N at an angle of 28° below the horizontal. If the coefficient of friction between the block and the ground is 0.17, find the acceleration of the block. **Diagram Explanation:** There is a diagram illustrating the scenario: - A block on the ground. - An arrow indicating a force being applied at an angle of 28° below the horizontal line representing the ground level. - The angle of 28° is marked between the arrow (force vector) and the horizontal. To solve this problem, begin by resolving the applied force into horizontal and vertical components. Then calculate the net force considering friction, and finally use Newton's second law to find the acceleration.
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