SOLUTIONS AND PURE SUBSTANCES TO2/S04 If 150 mL of 5.40 M aqueous HCI and 160 mL of 0.938 M aqueous Na2CO3 are reacted stoichiometrically according to the balanced equation, how many grams of liquid H20 are produced? Molar Mass (g/mol) 36.461 HCI NazCO3(aq) + 2HCI(aq) - CO2(g) + 2NACI(aq) + H2o(1) Na2CO3 105.99 Н2о 18.015 Density (g/mL) H20 0.9982 Molar Volume (L) 22.4 at STP Gas Constant (L'atm'mol"1-K*1) 0.0821 the tolerance is +/-2%

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
icon
Concept explainers
Question

Please help me, and double and triple check your answers previous tutors got questions wrong

SOLUTIONS AND PURE SUBSTANCES TO2/S04
If 150 mL of 5.40 M aqueous HCI and 160 mL of 0.938 M aqueous Na2CO3 are reacted stoichiometrically according to the balanced equation, how many grams of
liquid H20 are produced?
Molar Mass
(g/mol)
36.461
HCI
NazCO3(aq) + 2HCI(aq) - CO2(g) + 2NACI(aq) + H2o(1)
Na2CO3 105.99
Н2о
18.015
Density (g/mL)
H20 0.9982
Molar Volume (L)
22.4 at STP
Gas Constant
(L'atm'mol"1-K*1)
0.0821
the tolerance is +/-2%
Transcribed Image Text:SOLUTIONS AND PURE SUBSTANCES TO2/S04 If 150 mL of 5.40 M aqueous HCI and 160 mL of 0.938 M aqueous Na2CO3 are reacted stoichiometrically according to the balanced equation, how many grams of liquid H20 are produced? Molar Mass (g/mol) 36.461 HCI NazCO3(aq) + 2HCI(aq) - CO2(g) + 2NACI(aq) + H2o(1) Na2CO3 105.99 Н2о 18.015 Density (g/mL) H20 0.9982 Molar Volume (L) 22.4 at STP Gas Constant (L'atm'mol"1-K*1) 0.0821 the tolerance is +/-2%
Expert Solution
Step 1

Determine number of moles of each reactant:

1 mL = 0.001 L

Chemistry homework question answer, step 1, image 1

From the balanced equation, it is clear that 1 mol Na2CO3 reacts with 2 mol HCl.

Hence, 0.810 mol HCl has to react with 0.405 mol Na2CO3 but has only 0.150 mol Na2CO3. Therefore, Na2CO3 is the limiting reagent (excess HCl is present).

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Electronic Effects
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY