Solution Stoichiometry: Practice Questions Instructions Answer the following questions in the space provided. 1. What mass of gold is produced from the reaction of excess iron with 150 mL of 0.75 mol/L gold(III) nitrate solution?
Solution Stoichiometry: Practice Questions Instructions Answer the following questions in the space provided. 1. What mass of gold is produced from the reaction of excess iron with 150 mL of 0.75 mol/L gold(III) nitrate solution?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Step 1: Writing the given information,
First we have to write the balanced chemical equation between the iron and gold(III) nitrate
Fe + Au(NO3)3 → Fe(NO3)2 + 2Au
Balancing the above equation, we get
3Fe + 2Au(NO3)3 → 3Fe(NO3)2 + 2Au
Excess reactant: Fe
Concentration of gold (III) nitrate solution = 0.75 mol/L
Volume of gold (III) nitrate solution = 150 mL = 0.150 L
Note:
Molar mass of gold = 196.97 g/mol
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