2. _Zn +_HCl →_ZnCl2 +_H2 When 5.00g of zinc metal reacts with excess hydrochloric acid, how many grams of zinc chloride will be produced?

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Balance the chemical reaction, and complete the stoichiometry problem attached. 

 

### Problem: Stoichiometry of Zinc and Hydrochloric Acid Reaction

**Equation to Balance:**

\[ \_\_\_ \text{Zn} + \_\_\_ \text{HCl} \rightarrow \_\_\_ \text{ZnCl}_2 + \_\_\_ \text{H}_2 \]

**Problem Statement:**

When 5.00 g of zinc metal reacts with excess hydrochloric acid, how many grams of zinc chloride will be produced?

### Solution Steps:

1. **Balance the Chemical Equation:**

   First, balance the reaction to ensure that the number of atoms for each element is the same on both sides of the equation:

   \[ \text{Zn} + 2 \text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \]

2. **Calculate Molar Masses:**

   - Molar mass of Zn (Zinc): 65.38 g/mol
   - Molar mass of ZnCl₂ (Zinc Chloride): 
     - Zn: 65.38 g/mol
     - Cl: 35.45 g/mol \(\times\) 2 = 70.90 g/mol
     - Total: 65.38 g/mol + 70.90 g/mol = 136.28 g/mol

3. **Convert Grams of Zinc to Moles:**
   
   Use the molar mass of Zinc to find the number of moles:

   \[ \text{Moles of Zn} = \frac{5.00 \text{ g Zn}}{65.38 \text{ g/mol}} \approx 0.0765 \text{ mol Zn} \]

4. **Use the Stoichiometric Ratios:**

   According to the balanced equation, 1 mole of Zn produces 1 mole of ZnCl₂. Therefore, 0.0765 moles of Zn will produce 0.0765 moles of ZnCl₂.

5. **Convert Moles of ZnCl₂ to Grams:**

   Use the molar mass of ZnCl₂ to convert moles back to grams:

   \[ \text{Mass of ZnCl}_2 = 0.0765 \text{ mol ZnCl}_2 \times 136.28 \text{ g/mol} \approx 10.43 \text{ g ZnCl}_2
Transcribed Image Text:### Problem: Stoichiometry of Zinc and Hydrochloric Acid Reaction **Equation to Balance:** \[ \_\_\_ \text{Zn} + \_\_\_ \text{HCl} \rightarrow \_\_\_ \text{ZnCl}_2 + \_\_\_ \text{H}_2 \] **Problem Statement:** When 5.00 g of zinc metal reacts with excess hydrochloric acid, how many grams of zinc chloride will be produced? ### Solution Steps: 1. **Balance the Chemical Equation:** First, balance the reaction to ensure that the number of atoms for each element is the same on both sides of the equation: \[ \text{Zn} + 2 \text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \] 2. **Calculate Molar Masses:** - Molar mass of Zn (Zinc): 65.38 g/mol - Molar mass of ZnCl₂ (Zinc Chloride): - Zn: 65.38 g/mol - Cl: 35.45 g/mol \(\times\) 2 = 70.90 g/mol - Total: 65.38 g/mol + 70.90 g/mol = 136.28 g/mol 3. **Convert Grams of Zinc to Moles:** Use the molar mass of Zinc to find the number of moles: \[ \text{Moles of Zn} = \frac{5.00 \text{ g Zn}}{65.38 \text{ g/mol}} \approx 0.0765 \text{ mol Zn} \] 4. **Use the Stoichiometric Ratios:** According to the balanced equation, 1 mole of Zn produces 1 mole of ZnCl₂. Therefore, 0.0765 moles of Zn will produce 0.0765 moles of ZnCl₂. 5. **Convert Moles of ZnCl₂ to Grams:** Use the molar mass of ZnCl₂ to convert moles back to grams: \[ \text{Mass of ZnCl}_2 = 0.0765 \text{ mol ZnCl}_2 \times 136.28 \text{ g/mol} \approx 10.43 \text{ g ZnCl}_2
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