Solution: Nisha's Year 1-3 Costs Your Answer 9000 Your Answer 22500 Your Answer 140625 tn = 9000(2.5)^-1 t3 = 9000(2.5)³-1 t3 = 9000(2.5)² t3 = 9000(6.25) to = 9000(2.5)r1 tn = 9000(2.5)r-1 ti = 9000(2.5)'-1 t, = 9000(2.5)° t, = 9000(1) ti = $9,000 t2 = 9000(2.5)²-1 t2 = 9000(2.5)' tz = 9000(2.5) %| t2 = $22,500 t3 = $56,250

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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How did we get the exponent 6.5 in year three?

Solution: Nisha's Year 1-3 Costs
Your Answer
Your Answer
Your Answer
9000
22500
140625
tn = 9000(2.5)r-1
ti = 9000(2.5)-1
t, = 9000(2.5)°
t, = 9000(1)
tn = 9000(2.5)~1
t3 = 9000(2.5)³-
to = 9000(2.5)r-1
t2 = 9000(2.5)2-1
3-1
tz = 9000(2.5)'
t2 = 9000(2.5)
t3 = 9000(2.5)²
t3 = 9000(6.25)
ti = $9,000
t2 = $22,500
t3 = $56,250
Transcribed Image Text:Solution: Nisha's Year 1-3 Costs Your Answer Your Answer Your Answer 9000 22500 140625 tn = 9000(2.5)r-1 ti = 9000(2.5)-1 t, = 9000(2.5)° t, = 9000(1) tn = 9000(2.5)~1 t3 = 9000(2.5)³- to = 9000(2.5)r-1 t2 = 9000(2.5)2-1 3-1 tz = 9000(2.5)' t2 = 9000(2.5) t3 = 9000(2.5)² t3 = 9000(6.25) ti = $9,000 t2 = $22,500 t3 = $56,250
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