I need you to explain this step to me please EXAMPLE (2) Find the current through the 10-Q resistor of the network of Fig. (2).%3D10 2I35Ω.8Ω1Ω215 VFig.(2)Solution 1:(8 N + 3 N)I, – (8 N)I; – (3 N)I,( 8= 15 V%3D--(3 N + 5 N + 2 N)I, – (3 N)I, – (5 N)I; = 01: , -(8 Ω)1- -0--( 8 Ω + 10 Ω + 5Ω)1,(5 Ω),%3D111, – 813 – 31, = 15101, – 31, – 513 = 02313 - 81, – 51, = 0%3D-%3D--%3D111- 311 + 101,-811312 - 813 = 1551; = 051, + 231, = 0or-%3D11- 315-3108.-50.-andI3 = I100 =1.220 A%3D11-38.-310-58--523I need you to explain this step to meIiplease....

Mess analysis is an important method to solve big and complex circuits. According to KVL, the net…

Solution 1: (8 N + 3 N)I, (8 N)I; (3 N)/, ( 8 Ω)1 (3 N)I = 15 V I: (3 2 + 5N + 2 N)I, - (3 N)I, - (5 N2)I; = 0 (5 N)I, = 0 I3: (8 N + 10 n + 5 N)I, – (8 N)I, – (5 N)I, = 0 (5 Ω) %3D 111 - 813 – 31I, = 15 1012-31, - 513 = 0 2313-81- 51, = 0 %3D 111, - -31 + 1012 -81, 81, = 15 51, = 0 51, + 231, = 0 or 312 - - %3D %3D - 11 -3 15 10 8- -5 I3 = 1100 = 1.220 A %3D and -3 10 -81 -5 11 3 8- 23 -

Solution 1: (8 N + 3 N)I, (8 N)I; (3 N)/, ( 8 Ω)1 (3 N)I = 15 V I: (3 2 + 5N + 2 N)I, - (3 N)I, - (5 N2)I; = 0 (5 N)I, = 0 I3: (8 N + 10 n + 5 N)I, – (8 N)I, – (5 N)I, = 0 (5 Ω) %3D 111 - 813 – 31I, = 15 1012-31, - 513 = 0 2313-81- 51, = 0 %3D 111, - -31 + 1012 -81, 81, = 15 51, = 0 51, + 231, = 0 or 312 - - %3D %3D - 11 -3 15 10 8- -5 I3 = 1100 = 1.220 A %3D and -3 10 -81 -5 11 3 8- 23 -

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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