Solubility test H₂O CHCI H₂SO4 NaOH with light (1) + (7) (9) (3) (5) (10) (6) (11) (12) Compound 3-heptyne ethylbenzene 1-ethylcyclooctene (2) + isobutane (4) Halogenation/ Bromination (8) without light (13) (14) (15) (16) Reaction with Baeyer's Reagent Result Explanation (17) (20) (18) (21) (19) (22) no unsaturation
Solubility test H₂O CHCI H₂SO4 NaOH with light (1) + (7) (9) (3) (5) (10) (6) (11) (12) Compound 3-heptyne ethylbenzene 1-ethylcyclooctene (2) + isobutane (4) Halogenation/ Bromination (8) without light (13) (14) (15) (16) Reaction with Baeyer's Reagent Result Explanation (17) (20) (18) (21) (19) (22) no unsaturation
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Solubility test
H₂O CHCI3 H₂SO4
(1) +
(3)
(5)
+
(6)
(4)
Compound
3-heptyne
ethylbenzene
1-ethylcyclooctene (2)
isobutane
Halogenation/
Bromination
NaOH with light
(7)
(9)
(10)
(11)
(12)
(8)
without
light
(13)
(14)
(15)
(16)
Reaction with Baeyer's
Reagent
Result
Explanation
(17)
(20)
(18)
(21)
(19)
(22)
no unsaturation](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F96783bd7-38cf-41ac-b0df-cea8969951ca%2F9c5f12df-3360-4f3f-9aa5-64bb3e12bc46%2Fkfk22g_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Solubility test
H₂O CHCI3 H₂SO4
(1) +
(3)
(5)
+
(6)
(4)
Compound
3-heptyne
ethylbenzene
1-ethylcyclooctene (2)
isobutane
Halogenation/
Bromination
NaOH with light
(7)
(9)
(10)
(11)
(12)
(8)
without
light
(13)
(14)
(15)
(16)
Reaction with Baeyer's
Reagent
Result
Explanation
(17)
(20)
(18)
(21)
(19)
(22)
no unsaturation
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