Sol'n: eqn. 1 0 Q(+) = 0.107 (1000-) - 87 (1000- +)-6 @t= 300 mins. from 5hrs Q(300)=0.10761000-300)-87 (1000-300) - b = 74.9 kg V = 3500 -4 Definition of variables: CSTR Model Q() the amount of the quantity of salt dissolved in the well-mixed solution at time t (in minutes). V the initial volume a the amount of dissolved substance at time t be the concentration of the solution being poured in en inflow /-outflow + + 2 + ( √ ₁ = (²-1) ₁)e = n² di Model he where Q(0) - a Concentration 74.9 C

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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ean.
Sol'n:
O
Q(+) = 0.107 (1000-4) - 87 (1000- +)-6
@t= 300 mins. from Shus
Q(300)=0.107(1000-300)-87 (1000-300) - b
= 74.9k9
V=3500
-41
volume
V = 5000+(-30+25) (300).
D
Definition of variables: CSTR Model
Q(t)= the amount of the quantity of salt dissolved in the well-mixed solution at time t (in minutes).
V the initial volume
a= the amount of dissolved substance. time t
h the concentration of the solution being poured in
e= inflow
f outflow
Model:
do
dt
+(V₁+ (1-5)₁]e=
Q=he where Q(0) = a
Concentration.
74.9
3300
C =
|C
=
0.0214 kg/L
Transcribed Image Text:ean. Sol'n: O Q(+) = 0.107 (1000-4) - 87 (1000- +)-6 @t= 300 mins. from Shus Q(300)=0.107(1000-300)-87 (1000-300) - b = 74.9k9 V=3500 -41 volume V = 5000+(-30+25) (300). D Definition of variables: CSTR Model Q(t)= the amount of the quantity of salt dissolved in the well-mixed solution at time t (in minutes). V the initial volume a= the amount of dissolved substance. time t h the concentration of the solution being poured in e= inflow f outflow Model: do dt +(V₁+ (1-5)₁]e= Q=he where Q(0) = a Concentration. 74.9 3300 C = |C = 0.0214 kg/L
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