Solid Cacog is placed in a container and the reaction, CaCO3(s) = Cao (s) + CO2lg) reaches equilibrium at 1100 K when the pressure of CO, In the 10.0 L container is 1.00 atm. What will happen if the volume of the container is decreased to 5.00 L? O The pressure will fluctuate between 1.00 atm and 2.00 atm at regular intervals. O The pressure will increase at first and then decrease to a value greater than 1.00 atm. The pressure will increase at first and then decrease to 1.00 atm. The pressure will increase to 2.00 atm and remain at 2.00 atm O The pressure will not change at all.

Solid Cacog is placed in a container and the reaction, CaCO3(s) = Cao (s) + CO2lg) reaches equilibrium at 1100 K when the pressure of CO, In the 10.0 L container is 1.00 atm. What will happen if the volume of the container is decreased to 5.00 L? O The pressure will fluctuate between 1.00 atm and 2.00 atm at regular intervals. O The pressure will increase at first and then decrease to a value greater than 1.00 atm. The pressure will increase at first and then decrease to 1.00 atm. The pressure will increase to 2.00 atm and remain at 2.00 atm O The pressure will not change at all.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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CS 2( g) + 3Cl 2( g) <=> CCl 4( g) + S 2Cl 2( g) At a given temperature, the reaction above is at equilibrium when [CS2] = 0.075 M, [Cl2] = 0.35 M, [CCl4] = 0.25 M, and [S2Cl2] = 0.45 M. What will be the direction of the reaction when the reactants and products have the following concentrations: CS2 = 0.15 M, Cl2 = 0.15 M, CCl4 = 0.45M, and S2Cl2 = 0.31 M? I would like help with this problem I am solving for Kc and then Qc I believe. for Kc I set up the following equation using the molarity values in the brackets as (.25)(.45)/(.075)(.035)^3 and the Qc as (.45)(.31)/(.15)(.15)^3