solenoid whose length is L = 50 cm. 3 cm in radius and has 500 turns. This solenoid is flowed by a current of 10 A in the direction shown in the figure. What is the magnetic flux covered by the solenoid if the solenoid is considered to be very long
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a solenoid whose length is L = 50 cm. 3 cm in radius and has 500 turns. This solenoid is flowed by a current of 10 A in the direction shown in the figure. What is the magnetic flux covered by the solenoid if the solenoid is considered to be very long?
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- Chapter 30, Problem 067 A solenoid that is 77.1 cm long has a cross-sectional area of 15.7 cm². There are 974 turns of wire carrying a current of 5.98 A. (a) Calculate the energy density of the magnetic field inside the solenoid. (b) Find the total energy in joules stored in the magnetic field there (neglect end effects).The magnetic field inside an air-filled solenoid 40.0cm long and 3.00cm in diameter is 0.707 T. Approximately how much energy is stored in this field?An electric wire in the wall carries a DC current of 25A vertically upward. What is the Magnetic field due to the current at point P, 10 cm from the wire.
- A 150-turn solenoid carries a current of 12 A. The radius of the solenoid is 0.050 m; and its length is 0.18 m. Determine the magnetic flux through the circular cross-sectional area at the center of the solenoid.A solenoid is wound with 2300 turns per meter. When the current is 4.8 A, what is the magnetic field within the solenoid? Treat the solenoid as though it is infinitely long.A 1.0 m long metallic rod is rotated with an angular frequency of 400 rad s1 about an axis normal to the rod passing through its one end. The other end of the rod is in contact with a circular metallic ring. A constant and uniform magnetic field of .5 T parallel to the axis exists everywhere. Calculate the emf developed between the centre and the ring.
- A solenoid 2.5 cm in diameter and 30 cm in length has 2400 turns and carries a current of 2.0 A. A)Calculate the magnetic flux through the circular cross-sectional area of the solenoid. Hint: Assume this is a very long solenoid and use the simplified magnetic field formula for an infinite solenoid.A 2356 turn solenoid is carrying a current of 19.16 A. The solenoid is 38.07 cm long. What is the magnitude of the magnetic field (in milli-tesla) through the center of the solenoid?The magnetic field at the center of a solenoid L = 75 cm long is B = 0.11 T when a current of I = 3.5 A flows through the solenoid wire. 1. Solve the formula for the magnetic field near the center of a long, tightly wound solenoid for the number of turns, N, in the solenoid. The expression should be in terms of the given variables. 2. Calculate the value of the number of turns, N.
- A solenoid is wound with 670 turns, is 50cm long, and is 4cm in diameter as you look down its axis. The current produces a 4mT magnetic field at the center of the solenoid. The magnetic flux, in Tm2, (or Wb) in the solenoid is:A square loop,10.0cm on a side, is placed aroundthe center of a long solenoid which has 1500 turns of wire per meter. Thediameter of the solenoid is 9.00cm. The square coil has a resistance of 8.00. A cross section of the setup is shown toright. a.Determine the magnitude and the direction of the magnetic field inside the solenoid if it has a current of I=5.00 Amps in the direction shown. b.The initialcurrent through the solenoid is zero, at t =0 the current in the solenoid begins increasing according to the formulaI(t)=C1t2whereC1=5.00Amp/s2. Determine the magnitudeanddirectionof the current in the square coil at a time of .600 seconds.A circular piece of wire with radius 0.89 m has a 84.9 T magnetic field passing through. What is the maximum magnetic flux that can pass through this ring?