Let A =OA.11000- 112331 - 2-7 -12 -4-9 -513 -6 -11 -9 -13100327 2 03050791-9and B=031100-3 -7 -210 100003It can be shown that matrix A is row equivalent to matrix B. Find a basis for Col A.5-3 -50 0 0COB.32111990253OD.711320143

We know that col(A) is spaned by Linearly independent columns.

OO 0 171 - 1 3 1-2 2-4 -9-5 3 -6 1 2 3 w F O 0 7 2 0 -7 -1 3 1 -11 -9 -1 -7 O 3 - 2 -4 6 050 7 9 <- 11 1 -5 9 and B= 3 1 -3 -7 -2 0 1 01 0 0 00 5-3-5 0 50 035 K 0 It can be shown that matrix A is row equivalent to matrix B. Find a basis for REFER OB. OD. W723 -- 23 3 N +C 2 -4 6 2 -11

OO 0 171 - 1 3 1-2 2-4 -9-5 3 -6 1 2 3 w F O 0 7 2 0 -7 -1 3 1 -11 -9 -1 -7 O 3 - 2 -4 6 050 7 9 <- 11 1 -5 9 and B= 3 1 -3 -7 -2 0 1 01 0 0 00 5-3-5 0 50 035 K 0 It can be shown that matrix A is row equivalent to matrix B. Find a basis for REFER OB. OD. W723 -- 23 3 N +C 2 -4 6 2 -11

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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Question

Let A =
OA.
11
0
0
0
- 1
1
2
3
3
1 - 2
-7 -1
2 -4
-9 -5
1
3 -6 -11 -9 -1
3
1
0
0
3
2
7 2 0
3
0
5
0
7
9
1
-9
and B=
0
3
1
1
0
0
-3 -7 -2
1
0 1
0
0
0
0
3
It can be shown that matrix A is row equivalent to matrix B. Find a basis for Col A.
5-3 -5
0 0 0
C
OB.
3
2
11
1990
2
5
3
OD.
7
11
3
2014
3

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