So we already have two standard transforms L{a} = and L(*"} =. S-a 1 L{4} = "; L{#} = S-4 : [(4} =............; L{-5} =.....; L{e*} 5 L4-S} = -; L{e-2} =1 %3D s+2 Note that, as we said earlier, the Laplace transform is always an
So we already have two standard transforms L{a} = and L(*"} =. S-a 1 L{4} = "; L{#} = S-4 : [(4} =............; L{-5} =.....; L{e*} 5 L4-S} = -; L{e-2} =1 %3D s+2 Note that, as we said earlier, the Laplace transform is always an
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter6: Power Flows
Section: Chapter Questions
Problem 6.10MCQ
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![So we already have two standard transforms
1
L{a} = and L{"} =
%3D
%3!
S-a
L(4) - L44) -
4-S} = - L{e") =;z
1
:
. L{4} =.......;
L{e"} =
S-4
1
L{e-} =;
L{-5} =....;
L{e} =
S+2
Note that, as we said earlier, the Laplace transform is always an
expression in s.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffa851d5c-c86f-48c8-9b43-caa08d7e0312%2Fd8e96b63-085a-4893-9df9-4b0a41dad6bf%2F0blhdra_processed.jpeg&w=3840&q=75)
Transcribed Image Text:So we already have two standard transforms
1
L{a} = and L{"} =
%3D
%3!
S-a
L(4) - L44) -
4-S} = - L{e") =;z
1
:
. L{4} =.......;
L{e"} =
S-4
1
L{e-} =;
L{-5} =....;
L{e} =
S+2
Note that, as we said earlier, the Laplace transform is always an
expression in s.
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