Good day. I have a question on physics. I searched for the solution to this problem: A force of 36.ON acclerates a 6.0kg block at 7.0m/s2 along a boriztonal surface. How large is the friction force? and opened two solutions. It actually has the same answers but I am wondering if ff and fk are the same? Thank you.
Good day. I have a question on physics. I searched for the solution to this problem: A force of 36.ON acclerates a 6.0kg block at 7.0m/s2 along a boriztonal surface. How large is the friction force? and opened two solutions. It actually has the same answers but I am wondering if ff and fk are the same? Thank you.
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Good day.
I have a question on physics. I searched for the solution to this problem:
A force of 36.ON acclerates a 6.0kg block at 7.0m/s2 along a boriztonal surface. How large is the friction force?
and opened two solutions. It actually has the same answers but I am wondering if ff and fk are the same?
Thank you.
Transcribed Image Text:Dat a
given F = 36 N
}
ㅠ
ma
m =
But
a
6.к.д.
69
Since, the block is moving,
F-fk
=) |fk
= 7m/s2
Now; from.
fk
F-ma
6 kg
fk.
—
= UKN
from equation 1
58.8μK
икту
P
= ukx6x9.8
![Given
* The force applied on the block is F36N.
* The mass
of block is m = 6
The acceleration of block is a ==7 m/s².
The free body diagram of block is,
fret
m=6kg.
= ma
mg
The net force to calculated as
fret
F-ff=
= ma
2
36N-F₂ = 6kg x 7 m/s ²
36N-42N =
F=36N
ff
f = -6 N
Thus, the friction force is GN
[&R foration force]
[from Diagram, force in]
x dixchon & F-f
[-re sign shows only the
dixchien of friction
which is opposite of what
take ]
ное](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F11c8c014-645a-4fef-a79d-1002d8cccc7d%2F080e1004-043b-4382-a4d1-804334ce257a%2F03w8dsd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given
* The force applied on the block is F36N.
* The mass
of block is m = 6
The acceleration of block is a ==7 m/s².
The free body diagram of block is,
fret
m=6kg.
= ma
mg
The net force to calculated as
fret
F-ff=
= ma
2
36N-F₂ = 6kg x 7 m/s ²
36N-42N =
F=36N
ff
f = -6 N
Thus, the friction force is GN
[&R foration force]
[from Diagram, force in]
x dixchon & F-f
[-re sign shows only the
dixchien of friction
which is opposite of what
take ]
ное
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