SN123. Following declaration of an array of struct, assumes size of byte, short, int and long are 1, 2, 3 and 4 respectively. Alignment rule stipulates that n-byte field must be located at an address divisible by n. The fields in a struct are not rearranged, padding is used to ensure alignment. All elements of array should be of same size. Struct complx Short s Byte b Long I Int i End complx Complx C[10] Assuming C is located at an address divisible by 8, what is the total size of C, in Bytes?

Computer Networking: A Top-Down Approach (7th Edition)
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SN123. Following declaration of an array of struct, assumes size of byte, short, int and long are 1, 2, 3
and 4 respectively. Alignment rule stipulates that n-byte field must be located at an address divisible
by n. The fields in a struct are not rearranged, padding is used to ensure alignment. All elements of
array should be of same size.
Struct complx
Short s
Byte b
Long I
Int i
End complx
Complx C[10]
Assuming C is located at an address divisible by 8, what is the total size of C, in Bytes?
Transcribed Image Text:SN123. Following declaration of an array of struct, assumes size of byte, short, int and long are 1, 2, 3 and 4 respectively. Alignment rule stipulates that n-byte field must be located at an address divisible by n. The fields in a struct are not rearranged, padding is used to ensure alignment. All elements of array should be of same size. Struct complx Short s Byte b Long I Int i End complx Complx C[10] Assuming C is located at an address divisible by 8, what is the total size of C, in Bytes?
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