Σn=0 (2n +∞0 (-1)" x²n+1 , XER a. Find the Maclaurin series for x sin (x²) b. Approximate the value of 0.1 sin(0.01) using the 7th degree Maclaurin polynomial for x sin(x²) C. Differentiate the Maclaurin series for x sin (x²) to solve for the exact value of +1)! Σ 2n+1 ¹+∞ (−1)n(4n + 3)π²n+¹ (2n + 1)! n=0

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A: Recall : The geometric power series is 11−x=∑n=0∞xn,|x|<1

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Q: How do I solve this?

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