Smokers to quit smoking pemanently are listed. Assume the population standard deviation is 6.1 years. At a=0.02, is there enough evidence to reject the claim that the mean time it takes smokers to quit smoking permanently is 13 years? Complete parts (a) through (e). 20.4 7.1 79 18.9 20.2 13.3 8.8 20.4 D 16.6 19.5 88 18.4 17.4 15.7 224 17.6 8.7 7.6 20.7 12.7 18.5 15.8 18.6 15.5 21.7 122 12.5 10.5 9.8 8.1 15.7 8.1 O A. Ho: u> 13 (claim) Ha us 13- O B. H us 13 (daim) C. Họ = 13 (claim) H p> 13 H, u#13 O D. Ho: p#13 (claim) OE Hg. u213 (dlaim) H u<13 OF Ho >13 H us13 (claim) H, p= 13 (b) Identify the standardized test statistic. Use technology. z= (Round to two decimal places as needed.)

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The lengths of time (in years) it took a random sample of 32 former smokers to quit smoking permanently are listed. Assume the population standard deviation is 6.1 years. At α = 0.02, is there enough evidence to reject the claim that the mean time it takes smokers to quit smoking permanently is 13 years? Complete parts (a) through (e).

Data: 
20.4, 7.1, 7.9, 18.9, 20.2, 13.3, 8.8, 20.4, 16.6, 19.5, 8.8, 18.4, 17.7, 15.7, 22.4, 17.6, 8.7, 7.6, 20.7, 12.7, 18.5, 18.6, 15.6, 15.5, 21.7, 12.2, 12.5, 10.5, 9.8, 8.1, 15.7, 8.1

(a) Hypothesis Statements:

- **A.** \(H_0: \mu > 13\) (claim)  
  \(H_a: \mu \leq 13\)

- **B.** \(H_0: \mu \leq 13\) (claim)  
  \(H_a: \mu > 13\)

- **C.** \(H_0: \mu = 13\) (claim)  
  \(H_a: \mu \neq 13\)  ✔️

- **D.** \(H_0: \mu \neq 13\) (claim)  
  \(H_a: \mu = 13\)

- **E.** \(H_0: \mu \geq 13\) (claim)  
  \(H_a: \mu < 13\)

- **F.** \(H_0: \mu < 13\) (claim)  
  \(H_a: \mu \geq 13\)

(b) Identify the standardized test statistic. Use technology.

\(z =\) [\_\_\_] (Round to two decimal places as needed.)
Transcribed Image Text:The lengths of time (in years) it took a random sample of 32 former smokers to quit smoking permanently are listed. Assume the population standard deviation is 6.1 years. At α = 0.02, is there enough evidence to reject the claim that the mean time it takes smokers to quit smoking permanently is 13 years? Complete parts (a) through (e). Data: 20.4, 7.1, 7.9, 18.9, 20.2, 13.3, 8.8, 20.4, 16.6, 19.5, 8.8, 18.4, 17.7, 15.7, 22.4, 17.6, 8.7, 7.6, 20.7, 12.7, 18.5, 18.6, 15.6, 15.5, 21.7, 12.2, 12.5, 10.5, 9.8, 8.1, 15.7, 8.1 (a) Hypothesis Statements: - **A.** \(H_0: \mu > 13\) (claim) \(H_a: \mu \leq 13\) - **B.** \(H_0: \mu \leq 13\) (claim) \(H_a: \mu > 13\) - **C.** \(H_0: \mu = 13\) (claim) \(H_a: \mu \neq 13\) ✔️ - **D.** \(H_0: \mu \neq 13\) (claim) \(H_a: \mu = 13\) - **E.** \(H_0: \mu \geq 13\) (claim) \(H_a: \mu < 13\) - **F.** \(H_0: \mu < 13\) (claim) \(H_a: \mu \geq 13\) (b) Identify the standardized test statistic. Use technology. \(z =\) [\_\_\_] (Round to two decimal places as needed.)
Expert Solution
Step 1

Given

X be the length (in years) of smoking by farmers

 =20.4 , 7.1 , 7.9 , 18.9 , 20.2 , 13.3 , 8.8 , 20.4 , 16.6 , 19.5 , 8.8 , 18.4 , 17.4 , 15.7 , 22.4 , 17.6  , 

    8.7 , 7.6 , 20.7 , 12.7 , 18.5 , 15.8 , 18.6 , 15.5 , 21.7 , 12.2 , 12.5 , 10.5 , 9.8 , 8.1 , 15.7 , 8.1

 n=sample size = 32

σ= Population standard deviation of years of smoking by farmers =6.1

μ= Population mean of years of smoking b farmers

X¯ be the sample mean 

 

Step 2

We need to test the claim whether the mean length of time (in years) it take farmers to quit smoking is 13 years 

Therefore from the given option OPTION C is correct

That is

H0  : μ=13H1  : μ13

Since this hypothesis tests our claim that whether the mean time is equal or not equal to 13  and not whether it is greater or less than 13.

 

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